我是xml语言的新手,我有一个xml文件,我为该文件创建了xsd模式,但我的问题是如何在xml文件中引用这个模式.我的xml架构看起来像这样
<?xml version="1.0" encoding="utf-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:wmh="http://www.wmhelp.com/2003/eGenerator"
elementFormDefault="qualified"
targetNamespace="http://axis.com/service"
xmlns="http://axis.com/service"
version="1.0">
<xs:element name="SWService" type="SWServiceType"/>
<xs:element name="HWService" type="HWServiceType"/>
<xs:complexType name="SWServiceType">
<xs:sequence>
<xs:element name="Service" type="ServiceType" minOccurs="0" maxOccurs="unbounded"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="ServiceType">
<xs:complexContent>
<xs:extension base="IdType">
<xs:sequence>
<xs:element name="Description" type="xs:string" maxOccurs="1" minOccurs="0"/>
<xs:element name="ServiceCustomers" type="ServiceCustomersType" maxOccurs="1"
minOccurs="0"/>
<xs:element name="ServiceSuppliers" type="ServiceSuppliersType" maxOccurs="1"
minOccurs="0"/>
</xs:sequence>
<xs:attribute name="Name" type="xs:string" use="required"/>
</xs:extension>
</xs:complexContent>
</xs:complexType>
<xs:complexType name="HWServiceType">
<xs:sequence>
<xs:element name="element" type="elementGroupType" maxOccurs="1" minOccurs="0"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="ServiceCustomersType">
<xs:sequence>
<xs:element name="SoftWare" type="SoftWareType" maxOccurs="unbounded"
minOccurs="0"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="ServiceSuppliersType">
<xs:sequence>
<xs:element …Run Code Online (Sandbox Code Playgroud)