引用xml中的xsd文件

Question

我是xml语言的新手,我有一个xml文件,我为该文件创建了xsd模式,但我的问题是如何在xml文件中引用这个模式.我的xml架构看起来像这样

<?xml version="1.0" encoding="utf-8"?>
 <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:wmh="http://www.wmhelp.com/2003/eGenerator"
    elementFormDefault="qualified"
    targetNamespace="http://axis.com/service"
    xmlns="http://axis.com/service"
    version="1.0">

  <xs:element name="SWService" type="SWServiceType"/>
  <xs:element name="HWService" type="HWServiceType"/>


 <xs:complexType name="SWServiceType">
<xs:sequence>
  <xs:element name="Service" type="ServiceType" minOccurs="0" maxOccurs="unbounded"/>
  </xs:sequence>
  </xs:complexType>

 <xs:complexType name="ServiceType">
 <xs:complexContent>
 <xs:extension base="IdType">
  <xs:sequence>
    <xs:element name="Description" type="xs:string" maxOccurs="1" minOccurs="0"/>
    <xs:element name="ServiceCustomers" type="ServiceCustomersType" maxOccurs="1" 
 minOccurs="0"/>
    <xs:element name="ServiceSuppliers" type="ServiceSuppliersType" maxOccurs="1" 
 minOccurs="0"/>
  </xs:sequence>
  <xs:attribute name="Name" type="xs:string" use="required"/>
  </xs:extension>
  </xs:complexContent>
   </xs:complexType>

    <xs:complexType name="HWServiceType">
  <xs:sequence>
    <xs:element name="element" type="elementGroupType" maxOccurs="1" minOccurs="0"/>
  </xs:sequence>
  </xs:complexType>

  <xs:complexType name="ServiceCustomersType">
  <xs:sequence>
    <xs:element name="SoftWare" type="SoftWareType" maxOccurs="unbounded" 
  minOccurs="0"/>
  </xs:sequence>
  </xs:complexType>

  <xs:complexType name="ServiceSuppliersType">
  <xs:sequence>
    <xs:element name="SoftWare" type="SoftWareType" maxOccurs="unbounded" 
 minOccurs="0"/>
    <xs:element name="HardWare" type="HardWareType" maxOccurs="unbounded" 
  minOccurs="0"/>
  </xs:sequence>
 </xs:complexType>

 <xs:complexType name="SoftWareType">
 <xs:complexContent>
 <xs:extension base="PathType">
  <xs:attribute name="Service" type="xs:string" use="required"/>
    </xs:extension>
     </xs:complexContent>
 </xs:complexType>

 <xs:complexType name="HardWareType">
 <xs:complexContent>
 <xs:extension base="PathType">
  <xs:attribute name="Type" type="xs:string" use="required"/>
  <xs:attribute name="Nr" type="xs:string" use="required"/>
  <xs:attribute name="Service" type="xs:string" use="required"/>
    </xs:extension>
     </xs:complexContent>
 </xs:complexType>

<xs:complexType name="PathType">
  <xs:attribute name="Path" type="xs:string" use="required"/>
</xs:complexType>


   <xs:complexType name="elementGroupType">
 <xs:sequence>
       <xs:element name="element" type="elementType" maxOccurs="unbounded" 
 minOccurs="1"/>
  </xs:sequence>
 </xs:complexType>


 <xs:complexType name="elementType">
  <xs:sequence>
    <xs:element name="LM" type="LMType2" maxOccurs="1" minOccurs="1"/>
    <xs:element name="Service" type="ServiceType" maxOccurs="unbounded" minOccurs="0"/>
  </xs:sequence>
  <xs:attribute name="Type" type="xs:string" use="required"/>
  <xs:attribute name="Nr" type="xs:string" use="required"/>
  <xs:attribute name="Name" type="xs:string" use="required"/>
 </xs:complexType>


  <xs:complexType name="LMType2">
  <xs:sequence>
    <xs:element name="LowerMode" type="LowerModeType2" maxOccurs="unbounded" 
 minOccurs="0"/>
  </xs:sequence>
 </xs:complexType>

 <xs:complexType name="LowerModeType2">
 <xs:complexContent>
  <xs:extension base="IdType">
    <xs:attribute name="Probability" type="xs:double" use="required"/>
  </xs:extension>
  </xs:complexContent>
  </xs:complexType>


 <xs:complexType name="IdType">
  <xs:attribute name="Id" type="xs:string" use="required"/>
 </xs:complexType>

  </xs:schema>

我将此文件保存为service.xsd.我需要在我的xml文件中引用这个模式,我试过这样但它没有验证.

<?xml version="1.0" encoding="UTF-8"?>
<Service xsi:schemaLocation="file:///C:/main/newfolder/service.xsd"       
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://axis.com/service"        
 Version="1.0">
--------Xml data-------
 </Service>

我不知道是什么问题.它给出了这样的错误

  No DTD of the document found 

我试过这样的

<?xml version="1.0" encoding="UTF-8"?>
<Service xsi:schemaLocation=""http://axis.com/service"       
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://axis.com/service"        
 Version="1.0">
--------Xml data-------
 </Service>

但仍然是同样的问题.当我使用xmlpad验证xml文件时.任何人都可以解决我的问题.非常感谢

提前致谢.

Answer 1

schemaLocation 的使用完全是可选的，并且您的实例中的 Version 属性不正确（除非您在架构中定义了一个名为 Version 的属性）

以下实例

<Service xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://axis.com/service">
any string
</Service>

根据架构验证良好：

<?xml version="1.0" encoding="utf-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:wmh="http://www.wmhelp.com/2003/eGenerator"
    elementFormDefault="qualified"
    targetNamespace="http://axis.com/service"
    xmlns="http://axis.com/service"
    version="1.0">
  <xs:element name="Service" type="xs:string"/>
</xs:schema>

我所做的就是用字符串替换您的 AxisServiceType 类型。

为了确定您遇到的失败的确切原因，我需要查看您的整个架构和实例文档。