小编Nad*_*ard的帖子

我PostAsync()用来发送数据，代码完全按照它应该的方式执行。我将数据发送到的站点提供XML了成功或失败的响应通知。的XML响应是，像这样：甲成功的交返回1

<?xml version="1.0" encoding="utf-8" ?>
<result>
 <success>1</success>
 <uploadid/>
 </errors>
</result>

Run Code Online (Sandbox Code Playgroud)

而不成功返回<error>标签之间的原因

<?xml version="1.0" encoding="utf-8" ?>
<result>
 <success>0</success>
 <iploadid/>
 <errors>
    <error>File is not in correct format</error>
 </errors>
</result>

这是我用来执行我需要添加什么才能从页面读取响应的C#语法？PostAsync()XML

private void SendAsyncData()
{
  string connectionString = "Data Source=hmod;Initial Catalog=salesdb;uid=userid;password=password;MultipleActiveResultSets=True";
  DataTable grds = new DataTable();
  using (var con = new SqlConnection(connectionString))
  using (var cmd = new SqlCommand("procedureone", con))
  using (var da = new SqlDataAdapter(cmd))
  {
    cmd.CommandType …