从 PostAsync() 读取 XML 响应

Question

我PostAsync()用来发送数据，代码完全按照它应该的方式执行。我将数据发送到的站点提供XML了成功或失败的响应通知。的XML响应是，像这样：甲成功的交返回1

<?xml version="1.0" encoding="utf-8" ?>
<result>
 <success>1</success>
 <uploadid/>
 </errors>
</result>

而不成功返回<error>标签之间的原因

<?xml version="1.0" encoding="utf-8" ?>
<result>
 <success>0</success>
 <iploadid/>
 <errors>
    <error>File is not in correct format</error>
 </errors>
</result>

这是我用来执行我需要添加什么才能从页面读取响应的C#语法？PostAsync()XML

private void SendAsyncData()
{
  string connectionString = "Data Source=hmod;Initial Catalog=salesdb;uid=userid;password=password;MultipleActiveResultSets=True";
  DataTable grds = new DataTable();
  using (var con = new SqlConnection(connectionString))
  using (var cmd = new SqlCommand("procedureone", con))
  using (var da = new SqlDataAdapter(cmd))
  {
    cmd.CommandType = CommandType.StoredProcedure;
    da.Fill(grds);
  }
  var client = new HttpClient();
  var q = string.Empty;
  foreach (DataRow row in grds.Rows)
  {
    var parameterSet = new List<KeyValuePair<string, string>>();
    for (int i = 0; i < grds.Columns.Count; ++i)
    {
        parameterSet.Add(new KeyValuePair<string, string>(grds.Columns[i].ColumnName, row[i].ToString()));

    }

    var result = client.PostAsync("http://weneedsampledata/ashx", new FormUrlEncodedContent(parameterSet)).Result;
    string resultContent = result.Content.ReadAsStringAsync().Result;
  }
}

编辑
目前，即使接收数据的站点抛出错误，此语法也会返回代码 200（成功），我需要一种“读取”XML 响应的方法来确定数据是否实际成功。我试图在下面添加以读取响应，但它给了我一个编译错误：

“System.Net.Http.HttpResponseMessage”不包含“GetResponse”的定义，并且无法找到接受“System.Net.Http.HttpResponseMessage”类型的第一个参数的扩展方法“GetResponse”（您是否缺少 using 指令或汇编参考？）

var response = result.GetResponse();
Stream receiveStream = response.GetResponseStream();
StreamReader readStream = new StreamReader(receiveStream, Encoding.UTF8);
var postresult = readStream.ReadToEnd();
var xml = System.Xml.Linq.XElement.Parse(postresult);
if (xml.Elements("success").FirstOrDefault().Value == "1")
{
  lblgoodbad.Text = "It was good.";
}
else
{
  var errors = xml.Elements("errors");
  foreach (var error in errors.Elements("error"))
  {
    lblgoodbad.Text = error.Value;
  }
}

编辑 #2
感谢 @Hussey 的帮助 - 我只是对我的语法做了一个快速调整，它可以正常运行。我的完整语法如下：

    private void SendAsyncData()
{
  string connectionString = "Data Source=hmod;Initial Catalog=salesdb;uid=userid;password=password;MultipleActiveResultSets=True";
  DataTable grds = new DataTable();
  using (var con = new SqlConnection(connectionString))
  using (var cmd = new SqlCommand("procedureone", con))
  using (var da = new SqlDataAdapter(cmd))
  {
    cmd.CommandType = CommandType.StoredProcedure;
    da.Fill(grds);
  }
  var client = new HttpClient();
  var q = string.Empty;
  foreach (DataRow row in grds.Rows)
  {
    var parameterSet = new List<KeyValuePair<string, string>>();
    for (int i = 0; i < grds.Columns.Count; ++i)
    {
        parameterSet.Add(new KeyValuePair<string, string>(grds.Columns[i].ColumnName, row[i].ToString()));

    }

    var result = client.PostAsync("http://weneedsampledata/ashx", new FormUrlEncodedContent(parameterSet)).Result;
    string resultContent = result.Content.ReadAsStringAsync().Result;
    var xml = System.Xml.Linq.XElement.Parse(resultContent);
    if (xml.Elements("success").FirstOrDefault().Value == "1")
    {
      lblgoodbad.Text = "It was good.";
    }
    else
    {
      var errors = xml.Elements("errors");
      foreach (var error in errors.Elements("error"))
      {
        lblgoodbad.Text = error.Value;
      }
    }
  }
}

Answer 1

您可以添加这一行并尝试：

此行之后：

string resultContent = await result.Content.ReadAsStringAsync();

添加这个：

XElement incomingXml = XElement.Parse(resultContent);

或者，您也可以尝试使用 ReadAsStreamAsync 来将流读入 XmlDocument 中：

string resultContent = await result.Content.ReadAsStreamAsync();

XDocument incomingXml = XDocument.Load(resultContent);