小编rel*_*ima的帖子

我正在努力做一个进度条.

是否可以计算脚本上的执行行数并将每个执行行与一个函数相关联,以便每行或每5行执行一次？

我的计划是每次执行一行时更新进度条.

可能吗？我可以使用装饰器来做吗？

下面两种选择中的哪一种更有效？有什么建议可以进一步改进吗？

备选方案A:

for i in BAR_Items:
    if BAR_Items[i] != A and SHAPE[i+"_SHP"] != A: continue
    if i in Selection:
        Selection.remove(i)
        BAR_Items[i].clearActions()
        BAR_Items[i].add(vizact.spinTo(axisAngle=[0,1,0,90],speed=300))
        VFrame.SetStatusText(frame, i + " has been deselected. "+ str(Selection))
    else:
        Selection.append(i)
        BAR_Items[i].add(vizact.spin(0,1,0,90,viz.FOREVER))
        VFrame.SetStatusText(frame, i + " selected. " + str(Selection))
    break

备选方案B:

for i in BAR_Items:
    if BAR_Items[i] == A or SHAPE[i+"_SHP"] == A:
        if i in Selection:
            Selection.remove(i)
            BAR_Items[i].clearActions()
            BAR_Items[i].add(vizact.spinTo(axisAngle=[0,1,0,90],speed=300))
            VFrame.SetStatusText(frame, i + " has been deselected. "+ str(Selection))
        else:
            Selection.append(i)
            BAR_Items[i].add(vizact.spin(0,1,0,90,viz.FOREVER))
            VFrame.SetStatusText(frame, i + " selected. …

为什么在cursor.execute()之后执行两次cursor.fetchall()时什么也没有得到？有什么办法可以防止这种情况发生吗？我需要将信息存储在变量上吗？它应该这样工作吗？

我有很多列表,与气象站提供的列表完全相同.

但是,我如何将两个日常观察"合并"为一个？(第一组日常观察中可用的记录永远不会出现在第二组上).

['82294', '04/03/2002', '0000', '', '30.9', '', '', '', '26.1', '93', '1.554', '']
['82294', '04/03/2002', '1200', '24', '', '22', '', '', '', '', '', '']
['82294', '05/03/2002', '0000', '', '29.9', '', '', '', '25.62', '92.5', '0.863333', '']
['82294', '05/03/2002', '1200', '11', '', '23.2', '', '', '', '', '', '']
['82294', '06/03/2002', '0000', '', '31.6', '', '', '', '27.12', '87.5', '1.381333', '']
['82294', '06/03/2002', '1200', '0.2', '', '22.6', '', '', '', '', '', '']
['82294', '07/03/2002', '0000', '', '32.2', '', …

我一直在尝试优化以下两个嵌套循环:

def startbars(query_name, commodity_name):

     global h_list
     nc, s, h_list = [], {}, {}
     query = """ SELECT wbcode, Year, """+query_name+""" 
                 FROM innovotable WHERE commodity='"""+commodity_name+"""' and

                 """+query_name+""" != 'NULL' """
     rows = cursor.execute(query)
     for row in rows:
         n = float(row[2])
         s[str(row[0])+str(row[1])] = n
         nc.append(n)
     for iso in result:
         try:
             for an_year in xrange(1961, 2031, 1):
                 skey = iso+str(an_year)
                 h_list[skey] = 8.0 / max(nc) * s[skey]
         except:
             pass

有任何想法吗？谢谢.

这是我在sqlite/python中使用的查询:

Select wbCode from CountriesList_A

但是我希望有一些IF语句只返回在CountriesListB中的项目.

建议？非常感谢你.

这就是我一直在使用的:

for i in iter(SHAPES):
    SHAPES[i].drawOrder(97)
    SHAPES[i].alpha(CFG["SHP_alpha"])
    .
    .

这就是我的想法:

for i, v in app.SHAPES.items():
    v.drawOrder(97)
    v.alpha(CFG["SHP_alpha"])
    .
    .

我应该使用哪两个？有没有其他方法可以做到这一点？

如果我有一个字符串

mystring = "1212, 1215, 2132, 2312, 3333"

将其转换为列表的推荐方法是什么？如在

mylist = [1212, 1215, 2132, 2312, 3333]

请注意,mystring也可以采用单个值,如mystring ="1212"

当使用mechanize来改变表单中项目的状态时,我需要在Python中创建一个列表,如下所示:

['2009', '2008', '2007', '2006', '2005', '2004',]

列表必须以尾随逗号结尾,否则它将无效.例如,以下代码有效:

br = mechanize.Browser()
br.select_form(nr=0)
br['ctl03'] = ['2009', '2008', '2007',]

但是,以下代码不起作用:

br = mechanize.Browser()
br.select_form(nr=0)
br['ctl03'] = ['2009', '2008', '2007']

这是我不使用尾随逗号时得到的错误消息:

Traceback (most recent call last):
  File "C:/Users/Renato/PycharmProjects/Agrolink/faostat.py", line 43, in <module>
    br['ctl03$DesktopThreePanes1$ThreePanes$ctl01$TMyears'] = ['2009', '2008', '2007']
  File "C:\Python26\lib\site-packages\mechanize\_form.py", line 2782, in __setitem__
    control.value = value
  File "C:\Python26\lib\site-packages\mechanize\_form.py", line 1977, in __setattr__
    self._set_value(value)
  File "C:\Python26\lib\site-packages\mechanize\_form.py", line 1985, in _set_value
    raise TypeError("ListControl, must set a sequence")
TypeError: ListControl, must set a sequence
Process finished …

我该如何解决这个问题:

for i in LISTA and i not in LISTB:
   print i