我该如何解决这个问题:
for i in LISTA and i not in LISTB:
print i
Run Code Online (Sandbox Code Playgroud)
new_list = set(LISTA) - set(LISTB) # if you don't have duplicate
for i in new_list:
print i
Run Code Online (Sandbox Code Playgroud)
要么 :
for i in LISTA:
if i in LISTB:
continue
print i
Run Code Online (Sandbox Code Playgroud)
更复杂的解决方案.这是一个简单的交叉补充.
a = set([1, 2, 3])
b = set([3, 4, 5])
print(a - b)
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
192 次 |
| 最近记录: |