小编use*_*258的帖子

if hasattr(form, 'name') and hasattr(form, 'date'):
   print(form.name) #'Some name' - True
   print(form.date) #none - False

即使该hasattr(form, 'date')值为假,此条件也会验证为True .

验证倍数的正确方法是什么 hasattr?

$('.post-content').each(function () {
    var count = $(this).children().length;
    if (count > 1) {
        $(this).append("<span class='more'>More</span>");
        sel = $(this).children('p').slice(2);
        sel.hide();
    }
});


$(".more").click(function () {
    more = $(this);
    sel = $(this).parent().children('p').slice(2);
    console.log($(this))
    sel.slideToggle(function () {
        more.text("More");
    }, function () {
        more.text("Less");
    });
});

此代码工作正常,除非我尝试更改/更少.应该更多 - >更少 - >更多,我有更多 - >更少 - >更少

演示

http://jsfiddle.net/Y6TaU/

data = {'one': '1', 'two': '2', 'three': '3', 'four': '4', 'five': '5'}

keys = ('one', 'four')

unwanted = set(keys) - set(data)
for unwanted_key in unwanted: del data[unwanted_key]

我想要的输出是:

data = {'two': '2', 'three': '3', 'five': '5'}

我究竟做错了什么？

我正在使用这个接受的答案的代码.

DEMO

我在想什么:

args = ["4730/2", "17583/4"];

for (var i = 0; i < args.length; i++) {
    console.log('here');
    url = args[i] + "/";
};

console.log(url);

我需要连接一个字符串来生成这样的东西:

4730/2/17583/4/4730/2/17583/4

我怎样才能做到这一点？

http://jsfiddle.net/5npet/

我有这个代码:

    if opt1 is not None:
        user_a, db_a = opt1.split("/") 
        db_a = country_assoc(int(db_a))
        client_a = Client(None, user_a, db_a)
        data_client_a = client_a.get_user() 

    if opt2 is not None:
        user_b, db_b = opt2.split("/")  
        db_b = country_assoc(int(db_b))
        client_b = Client(None, user_b, db_b)
        data_client_b = client_b.get_user() 

    ....

但是,我想用循环生成类似的结构.

这样做的正确方法是什么？我正在尝试这个

    abcde = ['a', 'b', 'c', 'd', 'e']
    for idx, val in enumerate(abcde):
        if opt+idx is not None:
            user_+val, db_+val = opt+idx.split("/") 
            db_+val = country_assoc(int(db_+val))
            client_+val = Client(None, user_+val, db_+val)
            data_client_+val = client_+val.get_user()