我有这个代码:
if opt1 is not None:
user_a, db_a = opt1.split("/")
db_a = country_assoc(int(db_a))
client_a = Client(None, user_a, db_a)
data_client_a = client_a.get_user()
if opt2 is not None:
user_b, db_b = opt2.split("/")
db_b = country_assoc(int(db_b))
client_b = Client(None, user_b, db_b)
data_client_b = client_b.get_user()
....
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但是,我想用循环生成类似的结构.
这样做的正确方法是什么?我正在尝试这个
abcde = ['a', 'b', 'c', 'd', 'e']
for idx, val in enumerate(abcde):
if opt+idx is not None:
user_+val, db_+val = opt+idx.split("/")
db_+val = country_assoc(int(db_+val))
client_+val = Client(None, user_+val, db_+val)
data_client_+val = client_+val.get_user()
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我不明白为什么人们觉得有必要尝试这样做.变量名称不是数据.动态创建变量名永远不是一个好理由.
只需将您的值放在字典或列表中即可.
for idx, val in enumerate(abcde):
if opts[idx] is not None:
user, db = opts[idx].split("/")
users[val] = user
dbs[val] = country_assoc(int(db))
clients[val] = Client(None, user, db)
data_clients.append(clients[val].get_user())
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