我想在Bootstrap 4中使用datepicker https://bootstrap-datepicker.readthedocs.io/en/latest/index.html。
按照上一页中的示例，我可以使其与Bootstrap 3一起使用。
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<link href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.7.1/css/bootstrap-datepicker.min.css" rel="stylesheet"/>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
</head>
<body>
<main class="container">
<div class="row" style="padding-top: 100px">
<div class="col">
<input data-date-format="dd/mm/yyyy" id="datepicker">
</div>
</div>
</main>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.7.1/js/bootstrap-datepicker.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js" integrity="sha384-Tc5IQib027qvyjSMfHjOMaLkfuWVxZxUPnCJA7l2mCWNIpG9mGCD8wGNIcPD7Txa" crossorigin="anonymous"></script>
<script type="text/javascript">
$('#datepicker').datepicker({
weekStart: 1,
daysOfWeekHighlighted: "6,0",
autoclose: true,
todayHighlight: true,
});
$('#datepicker').datepicker("setDate", new Date());
</script>
</body>使用此代码datepicker会正确显示。
但是对Bootstrap 4进行相同的操作：
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, …我使用Roo创建了一个使用现有数据库的项目.我能够创建动态查找器,但我想实现自定义查找程序,它将接收4个参数并使用其中一些来创建Like条件,其他参数为equals条件.
使用Roo的最佳方法是什么？
我正在使用 Spring Cloud Contract Verifier
org.springframework.cloud:spring-cloud-starter-contract-verifier:jar:2.0.0.M8 org.springframework.cloud:spring-cloud-contract-maven-plugin:1.2.4.RELEASE
我有以下合同：
request:
method: GET
url: /cars/list
response:
status: 200
headers:
Content-Type: application/json;charset=UTF-8
body:
cars:
[
{
"make": "Ford",
"model": "Fiesta",
"year": 2016,
"price": 16500.50
},
{
"make": "BMW",
"model": "X1",
"year": 2014,
"price": 22000.00
},
{
"make": "NISSAN",
"model": "Juke",
"year": 2017,
"price": 19300.00
}
]
然后在以下java代码中转换：
DocumentContext parsedJson = JsonPath.parse(response.getBody().asString());
assertThatJson(parsedJson).array("['cars']").contains("['model']").isEqualTo("Juke");
assertThatJson(parsedJson).array("['cars']").contains("['make']").isEqualTo("Ford");
assertThatJson(parsedJson).array("['cars']").contains("['year']").isEqualTo(2014);
assertThatJson(parsedJson).array("['cars']").contains("['year']").isEqualTo(2016);
assertThatJson(parsedJson).array("['cars']").contains("['model']").isEqualTo("Fiesta");
assertThatJson(parsedJson).array("['cars']").contains("['make']").isEqualTo("BMW");
assertThatJson(parsedJson).array("['cars']").contains("['year']").isEqualTo(2017);
assertThatJson(parsedJson).array("['cars']").contains("['make']").isEqualTo("NISSAN");
assertThatJson(parsedJson).array("['cars']").contains("['price']").isEqualTo(16500.5);
assertThatJson(parsedJson).array("['cars']").contains("['model']").isEqualTo("X1");
assertThatJson(parsedJson).array("['cars']").contains("['price']").isEqualTo(22000.0);
assertThatJson(parsedJson).array("['cars']").contains("['price']").isEqualTo(19300.0);
我对这个测试有几个问题：
1）它不考虑顺序，这意味着以下机构仍将被视为有效：
{
"cars": [
{
"make": "NISSAN",
"model": "Juke", …我正在构建使用JPA的应用程序,我想使用http://openjpa.apache.org/builds/latest/docs/manual/jpa_overview_criteria.html中描述的Criteria API .更确切地说,这部分:
EntityManager em = ... ;
CriteriaBuilder queryBuilder = em.getCriteriaBuilder();
CriteriaQuery qdef = queryBuilder.createCriteriaQuery();
问题是,有没有getCriteriaBuilder()在我的方法EntityManager,也CriteriaBuilder并CriteriaQuery不能在找到persistance-api-1.0.jar
我错过了什么？因为我正在使用一个错误的罐子？我的来自http://repo2.maven.org/maven2/javax/persistence/persistence-api/1.0/
Regrads,Oleksandr