如何在PHP5中链接对象:$ this-> foo-> bar-> baz()

Question

如何在PHP5类中创建链接对象？例子:

$myclass->foo->bar->baz();
$this->foo->bar->baz();
Not: $myclass->foo()->bar()->baz();

另见:http:
//www.talkphp.com/advanced-php-programming/1163-php5-method-chaining.html

Answer 1

实际上这个问题含糊不清......对我而言,@ Geo的答案是对的.

你(@Anti)说的可能是作曲

这是我的例子:

<?php
class Greeting {
    private $what;
    private $who;


    public function say($what) {
        $this->what = $what;
        return $this;
    }

    public function to($who) {
        $this->who = $who;
        return $this;
    }

    public function __toString() {
        return sprintf("%s %s\n", $this->what, $this->who);
    }

}

$greeting = new Greeting();
echo $greeting->say('hola')->to('gabriel'); // will print: hola gabriel

？>

Answer 2

只要你的$ myclass有一个成员本身就是一个实例,它就会像那样工作.

class foo {
   public $bar;
}

class bar {
    public function hello() {
       return "hello world";
    }
}

$myclass = new foo();
$myclass->bar = new bar();
print $myclass->bar->hello();