我有一个看起来像thos的查询:
SELECT max(insert_date),
creative_id,
creative_object
FROM rtb_creatives
WHERE adgroup_id = 'agid1608844879'
AND is_delete IN ( 0 )
GROUP BY insert_date,
creative_id,
creative_object
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例如,我有4行:insert_date creative_id,creative_object
june 12 a b
june13 a b
june 12 c d
june13 c d
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查询返回所有行.
我需要回来
june13 a b
june13 c d
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如何修改查询?
只需insert_date从GROUP BY子句中删除:
SELECT max(insert_date) AS insert_date, creative_id, creative_object
from rtb_creatives
where adgroup_id='agid1608844879' and is_delete in (0)
group by creative_id, creative_object
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