XmlSerializer.Serialize剥离<xml>标记

Question

我正在尝试与支付处理器进行通信.当我XmlSerializer.Serialize 在我的物体上使用时,我得到了

<?xml version=\"1.0\" encoding=\"utf-16\"?>
<txn xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">
  <ssl_merchant_id>xxxxxx</ssl_merchant_id>
  <ssl_user_id>xxxxxx</ssl_user_id>
  <ssl_pin>xxxxxx</ssl_pin>
  <ssl_test_mode>True</ssl_test_mode>
  <ssl_transaction_type>ccavsonly</ssl_transaction_type>
  <ssl_card_number>4111111111111111</ssl_card_number>
  <ssl_exp_date>0612</ssl_exp_date>
  <ssl_avs_address>101 Main St.</ssl_avs_address>
  <ssl_avs_zip>90210</ssl_avs_zip>
</txn>

在使用该方法之前,我手动构建了XML以进行测试,这有效:

<txn>
  <ssl_merchant_id>xxxxxx</ssl_merchant_id>
  <ssl_user_id>xxxxxx</ssl_user_id>
  <ssl_pin>xxxxxx</ssl_pin>
  <ssl_test_mode>True</ssl_test_mode>
  <ssl_transaction_type>ccavsonly</ssl_transaction_type>
  <ssl_card_number>4111111111111111</ssl_card_number>
  <ssl_exp_date>0612</ssl_exp_date>
  <ssl_avs_address>101 Main St.</ssl_avs_address>
  <ssl_avs_zip>90210</ssl_avs_zip>
</txn>

我怎么会去剥离出来<?xml version=\"1.0\" encoding=\"utf-16\"?>,并xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">从XML或不具备串行产生它开始？

我的对象看起来像:

[XmlRoot(ElementName="txn")]
public class AvsTransmission
{
    [XmlElement]
    public string ssl_merchant_id { get; set; }
    [XmlElement]
    public string ssl_user_id { get; set; }
    [XmlElement]
    public string ssl_pin { get; set; }
    [XmlElement]
    public string ssl_test_mode { get; set; }
    [XmlElement]
    public string ssl_transaction_type { get; set; }
    [XmlElement]
    public string ssl_card_number { get; set; }
    [XmlElement]
    public string ssl_exp_date { get; set; }
    [XmlElement]
    public string ssl_avs_address { get; set; }
    [XmlElement]
    public string ssl_avs_zip { get; set; }
}

Answer 1

我的第一个答案只是问题的一半,你还必须删除已提到的声明.

这是一个例子:

XmlWriterSettings settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;

MemoryStream ms = new MemoryStream();
XmlWriter writer = XmlWriter.Create(ms, settings);

XmlSerializerNamespaces names = new XmlSerializerNamespaces();
names.Add("", "");

XmlSerializer cs = new XmlSerializer(typeof(Cat));

cs.Serialize(writer, new Cat { Lives = 9 }, names);

ms.Flush();
ms.Seek(0, SeekOrigin.Begin);
StreamReader sr = new StreamReader(ms);
var xml = sr.ReadToEnd();

该字符串xml现在包含:

<cat><Lives>9</Lives></cat>

Answer 2

第一个函数将对象转换为 xml 字符串，第二个函数转换对象并同时将 xml 写入文件。

    public static string Serialize<T>(T obj)
    {
        XmlWriterSettings settings = new XmlWriterSettings();
        settings.OmitXmlDeclaration = true;
        var writer = new StringWriter();
        XmlWriter xmlWriter = XmlWriter.Create(writer, settings);

        XmlSerializerNamespaces names = new XmlSerializerNamespaces();
        names.Add("", "");

        XmlSerializer serializer = new XmlSerializer(typeof(T));

        serializer.Serialize(xmlWriter, obj, names);
        var xml = writer.ToString();
        return xml;
    }

    public static void Serialize<T>(T obj, string filepath)
    {
        XmlWriterSettings settings = new XmlWriterSettings();
        settings.OmitXmlDeclaration = true;
        var writer = new StreamWriter(filepath);
        XmlWriter xmlWriter = XmlWriter.Create(writer, settings);

        XmlSerializerNamespaces names = new XmlSerializerNamespaces();
        names.Add("", "");

        XmlSerializer serializer = new XmlSerializer(typeof(T));

        serializer.Serialize(xmlWriter, obj, names);
    }

实际上我意识到代码重复了自己。在这些方法中，仅更改 writer 对象，因此代码必须如下所示。这样，您只需更改 writer 对象类型即可轻松使用代码。

    public static string Serialize<T>(T obj)
    {
        var writer = new StringWriter();
        Serialize<T>(obj,writer);
        var xml = writer.ToString();
        return xml;
    }

    public static void Serialize<T>(T obj, string filepath)
    {
        var writer = new StreamWriter(filepath);
        Serialize<T>(obj,writer);
    }

    public static void Serialize<T>(T obj, TextWriter writer)
    {
        XmlWriterSettings settings = new XmlWriterSettings();
        settings.OmitXmlDeclaration = true;
        XmlWriter xmlWriter = XmlWriter.Create(writer, settings);            
        XmlSerializerNamespaces names = new XmlSerializerNamespaces();
        names.Add("", "");            
        XmlSerializer serializer = new XmlSerializer(typeof(T));            
        serializer.Serialize(xmlWriter, obj, names);
    }

Answer 3

与@payo的原始答案非常相似：

如果您想删除名称空间，您可能还想删除版本，为了节省您的搜索，我添加了该功能，因此下面的代码将同时执行这两个操作。

我还将它包装在一个通用方法中，因为我正在创建非常大的 xml 文件，这些文件太大而无法在内存中序列化，因此我将输出文件分解并将其序列化为较小的“块”：

public string XmlSerialize<T>(T entity) where T : class
{
    // removes version
    XmlWriterSettings settings = new XmlWriterSettings();
    settings.OmitXmlDeclaration = true;

    XmlSerializer xsSubmit = new XmlSerializer(typeof(T));
    StringWriter sw = new StringWriter();
    using (XmlWriter writer = XmlWriter.Create(sw, settings))
    {
        // removes namespace
        var xmlns = new XmlSerializerNamespaces();
        xmlns.Add(string.Empty, string.Empty);

        xsSubmit.Serialize(writer, entity, xmlns);
        return sw.ToString(); // Your XML
    }
}