如何在C#中使用&运算符？代码的翻译是否正确？

Question

C++中的"if(arg2&1)"行(arg2是DWORD)等于C#中的"if(arg2&1 == 0)"(arg2是Uint32),对吧？

我正在尝试将函数从C++转换为C#,但是我收到一个错误:

Operator '&' cannot be applied to operands of type 'uint' and 'bool'

如果你能在整个功能中看到任何其他错误,我也会感激不尽.

C++

DWORD Func_X_4(DWORD arg1, DWORD arg2, DWORD arg3)
{
LARGE_INTEGER result = {1, 0};
LARGE_INTEGER temp1 = {0};
LARGE_INTEGER temp2 = {0};
LARGE_INTEGER temp3 = {0};
LARGE_INTEGER temp4 = {0};
for(int x = 0; x < 32; ++x)
{
    if(arg2 & 1)
    {
        temp1.LowPart = arg3;
        temp1.HighPart = 0;
        temp2.QuadPart = temp1.QuadPart * result.QuadPart;
        temp3.LowPart = arg1;
        temp3.HighPart = 0;
        temp4.QuadPart = temp2.QuadPart % temp3.QuadPart;
        result.QuadPart = temp4.QuadPart;
    }
    arg2 >>= 1;
    temp1.LowPart = arg3;
    temp1.HighPart = 0;
    temp1.QuadPart *= temp1.QuadPart;
    temp2.LowPart = arg1;
    temp2.HighPart = 0;
    temp3.QuadPart = temp1.QuadPart % temp2.QuadPart;
    arg3 = temp3.LowPart;
    if(!arg2)
        break;
}
return result.LowPart;
}

转换为C#

LARGE_INTEGER结构:

[StructLayout(LayoutKind.Explicit, Size = 8)]
public struct LARGE_INTEGER
{
    [FieldOffset(0)]
    public Int64 QuadPart;
    [FieldOffset(0)]
    public UInt32 LowPart;
    [FieldOffset(4)]
    public Int32 HighPart;
}

功能:

public static UInt32 X4(UInt32 arg1, UInt32 arg2, UInt32 arg3)
    {
        LARGE_INTEGER result = new LARGE_INTEGER();
        result.LowPart = 1;
        result.HighPart = 0;
        LARGE_INTEGER temp1 = new LARGE_INTEGER();
        LARGE_INTEGER temp2 = new LARGE_INTEGER();
        LARGE_INTEGER temp3 = new LARGE_INTEGER();
        LARGE_INTEGER temp4 = new LARGE_INTEGER();
        for (int x = 0; x < 32; ++x)
        {
            if (arg1 & 1 ==0)
            {
                temp1.LowPart = arg3;
                temp1.HighPart = 0;
                temp2.QuadPart = temp1.QuadPart * result.QuadPart;
                temp3.LowPart = arg1;
                temp3.HighPart = 0;
                temp4.QuadPart = temp2.QuadPart % temp3.QuadPart;
                result.QuadPart = temp4.QuadPart;
            }
            arg2 >>= 1;
            temp1.LowPart = arg3;
            temp1.HighPart = 0;
            temp1.QuadPart *= temp1.QuadPart;
            temp2.LowPart = arg1;
            temp2.HighPart = 0;
            temp3.QuadPart = temp1.QuadPart % temp2.QuadPart;
            arg3 = temp3.LowPart;
            if (arg2==0)
                break;
        }
        return result.LowPart;
    }

这是我还不确定的事情:

1. C++中的DWORD是否是UI#32或C#中的Int32？
2. if(整数和整数)表示if(整数和整数== 0)？//这是我上面描述的错误的位置.
3. if(!integer)表示if(integer!= 0)？
4. 为什么运算符&不能在C#中逻辑使用,这意味着它需要一个布尔值？
5. "LARGE_INTEGER result = {1,0}"表示result.lowpart为1且result.highpart为0或result.Quadpart = 1？

提前致谢!

Answer 1

你写的地方:

if(arg1&arg2 == 0)

编译器理解:

if (arg1 & (arg2==0))

你应该写:

if ((arg1 & arg2) == 0)

这是将C++语句转换为C#的方式:

if (arg2 & 1) // C++ (arg2 is DWORD)
if ((arg2 & 1) != 0) // C# (arg2 is Uint32)

或者,以更通用的方式:

if (Flags & FlagToCheck) // C++
if ((Flags & FlagToCheck) != 0) // C#

在C/C++中,0为假,其他一切都为真.

1. 你应该检查DWORD的定义,它应该是(unsigned int),它是C#中的UInt32
2. if(整数和整数),在C/C++中表示"如果按位的结果和两个整数之间的结果不是0"(0为假,其他一切都为真).
3. if(!integer)表示if(integer == 0)(同样,0表示false,其他一切都为true)
4. 在C#中,就像在Java中我认为,布尔值和数字是两个不同的东西,你只能在"if"语句中使用布尔值,如果使用int则没有隐式转换:它不会编译.
5. 我会把这个留给别人,我需要测试以确定......