Vin*_*nce 10 python go python-3.x cgo
我试图在 python 的 go 脚本中运行一个简单的程序,但出现了分段错误。这是我的代码:
main.go
package main
import (
/*
typedef struct foo{
int a;
int b;
int c;
int d;
int e;
int f;
} foo;
*/
"C"
)
func main() {}
//export Foo
func Foo(t []int) C.foo {
return C.foo{}
}
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主文件
# loading shared object
lib = cdll.LoadLibrary("main.so")
# go type
class GoSlice(Structure):
_fields_ = [("data", POINTER(c_void_p)), ("len", c_longlong), ("cap", c_longlong)]
lib.Foo.argtypes = [GoSlice]
lib.Foo.restype = c_void_p
t = GoSlice((c_void_p * 5)(1, 2, 3, 4, 5), 5, 5)
f = lib.Foo(t)
print(f)
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有了那个代码,我得到了
140362617287784
[1] 23067 segmentation fault python3 main.py
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现在如果我删除e并f从main.go我得到
None
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并且没有更多的分段错误。
为什么结构中的成员数量在这里很重要?
[编辑] 两者都在同一个地方运行,我运行一个命令 clear && go build -o main.so -buildmode=c-shared main.go && python3 main.py
geo*_*eok 11
您的 GO/C 代码是正确的。问题出在python脚本中。该lib.Foo.restype = c_void_p调用需要一个空指针,但库返回一个 C 结构。您需要在 python 中定义一个 ctypes 结构的返回类型,然后它将按您的预期工作。
该main.go:
package main
import (
/*
typedef struct foo{
int a;
int b;
int c;
int d;
int e;
int f;
} foo;
*/
"C"
)
func main() {
}
//export Foo
func Foo(t []int) C.foo {
foo := C.foo{}
foo.a = 1 // setting some values to avoid seeing zeros
foo.b = 2
return foo
}
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主要.py:
from ctypes import *
# loading shared object
lib = cdll.LoadLibrary("main.so")
# go type
class GoSlice(Structure):
_fields_ = [("data", POINTER(c_void_p)), ("len", c_longlong), ("cap", c_longlong)]
class Foo(Structure):
_fields_ = [('a', c_int),
('b', c_int),
('c', c_int),
('d', c_int),
('e', c_int),
('f', c_int)]
lib.Foo.argtypes = [GoSlice]
lib.Foo.restype = Foo
t = GoSlice((c_void_p * 5)(1, 2, 3, 4, 5), 5, 5)
f = lib.Foo(t)
print(f)
print(f.a)
print(f.b)
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然后运行go build -o main.so -buildmode=c-shared main.go && python main.py,它会打印:
go build -o main.so -buildmode=c-shared main.go && python3 main.py
<__main__.Foo object at 0x102608830>
1
2
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