如何使用Linq选择最接近指定日期的记录?这适用于具有日期,产品ID,位置ID和余额的交易表.
鉴于这些要求:
表数据:
// code
Id, TransDateTime, ProductId, WarehouseId, Balance
1, 1-Jan-2011 00:00, 1, 1, 100
2, 1-Jan-2011 00:00, 1, 2, 10
3, 2-Jan-2011 00:00, 1, 1, 150
4, 3-Jan-2011 00:00, 1, 2, 25
5, 3-Jan-2011 00:00, 2, 1, 333
6, 7-Jan-2011 00:00, 1, 1, 149
7, 7-Jan-2011 01:00, 1, 2, 30
8, 7-Jan-2011 02:00, 1, 2, 35
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测试日期和输出
Date: 1-Jan would output:
1, 1-Jan-2011 00:00, 1, 1, 100
2, 1-Jan-2011 00:00, 1, 2, 10
Date: 3-Jan would output:
3, 2-Jan-2011 00:00, 1, 1, 150
4, 3-Jan-2011 00:00, 1, 2, 25
5, 3-Jan-2011 00:00, 2, 1, 333
// product 1, warehouse 1 wasn't sold on the 3rd
// so the row from 2-Jan is returned
Date: 7-Jan would output:
5, 3-Jan-2011 00:00, 2, 1, 333
6, 7-Jan-2011 00:00, 1, 1, 149
9, 7-Jan-2011 02:00, 1, 2, 35
// product 2, warehouse 1 wasn't sold on the 7th
// so the row from 3-Jan is returned
// product 1, warehouse 2 was sold twice on the 7th
// so the later one is used
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我认为这需要分组(产品 - >仓库 - >日期)或类似的.它超出了我的linq能力!
步骤:
1)过滤掉inputDate
2)按产品和仓库分组剩余交易后发生的交易
3)在每个组中查找最近的事务
4)格式化结果对象
直截了当的实施:
DateTime inputDate = ...;
var result = transactions
.Where(t => t.TransDateTime.Date <= inputDate.Date)
.GroupBy(t => new {t.ProductId, t.WarehouseId})
.Select(x => new {
x.Key,
LastTransaction = x.OrderByDescending(t => t.TransDateTime).First(),
})
.Select(x => new {
Id = x.LastTransaction.Id,
Date = x.LastTransaction.TransDateTime,
ProductId = x.Key.ProductId,
WarehouseId = x.Key.WarehouseId,
Balance = x.LastTransaction.Balance,
});
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如果您想要进行一些优化,可以考虑实现要替换的MaxBy扩展方法.如果您有许多交易,它将提高性能,因为它代替.这里可以实现实现,例如:C#中的简单LINQ问题IEnumerablex.OrderByDescending(t => t.TransDateTime).First()O(n)O(n log n)MaxBy