如何使用seaborn为我的DataFrame创建堆积条形图？

Question

我有一个DataFrame df:

df = pd.DataFrame(columns=["App","Feature1", "Feature2","Feature3",
                           "Feature4","Feature5",
                           "Feature6","Feature7","Feature8"], 
                  data=[["SHA",0,0,1,1,1,0,1,0],
                        ["LHA",1,0,1,1,0,1,1,0],
                        ["DRA",0,0,0,0,0,0,1,0],
                        ["FRA",1,0,1,1,1,0,1,1],
                        ["BRU",0,0,1,0,1,0,0,0],
                        ["PAR",0,1,1,1,1,0,1,0],
                        ["AER",0,0,1,1,0,1,1,0],
                        ["SHE",0,0,0,1,0,0,1,0]])

我想创建一个堆积条形图,以便每个堆栈对应于AppY轴将包含1值的计数和X轴Feature.

它应该类似于这个条形图,唯一的区别是现在我想看到堆栈条和带颜色的图例:

df_c = df.iloc[:, 1:].eq(1).sum().rename_axis('Feature').reset_index(name='Cou??nt')
df_c = df_c.sort_values('Count')

plt.figure(figsize=(12,8))
ax = sns.barplot(x="Feature", y="Count", data=df_c, palette=sns.color_palette("GnBu", 10))
plt.xticks(rotation='vertical')
ax.grid(b=True, which='major', color='#d3d3d3', linewidth=1.0)
ax.grid(b=True, which='minor', color='#d3d3d3', linewidth=0.5)
plt.show()

Answer 1

您可以使用pandas plot作为@Bharath建议:

import seaborn as sns
sns.set()
df.set_index('App').T.plot(kind='bar', stacked=True)

输出:

更新:

来自matplotlib.colors import ListedColormap df.set_index('App')\ .reindex_axis(df.set_index('App').sum().sort_values().index,axis = 1)\ .T.plot(kind =' bar',stacked = True,colormap = ListedColormap(sns.color_palette("GnBu",10)),figsize =(12,6))

reindex_axis已弃用更新后的Pandas 0.21.0+ ,请使用reindex

from matplotlib.colors import ListedColormap

df.set_index('App')\
  .reindex(df.set_index('App').sum().sort_values().index, axis=1)\
  .T.plot(kind='bar', stacked=True,
          colormap=ListedColormap(sns.color_palette("GnBu", 10)), 
          figsize=(12,6))

输出: