jrj*_*rjc 46 python plot matplotlib pandas seaborn
所以这是我的数据集的样子:
In [1]: df1=pd.DataFrame(np.random.rand(4,2),index=["A","B","C","D"],columns=["I","J"])
In [2]: df2=pd.DataFrame(np.random.rand(4,2),index=["A","B","C","D"],columns=["I","J"])
In [3]: df1
Out[3]:
I J
A 0.675616 0.177597
B 0.675693 0.598682
C 0.631376 0.598966
D 0.229858 0.378817
In [4]: df2
Out[4]:
I J
A 0.939620 0.984616
B 0.314818 0.456252
C 0.630907 0.656341
D 0.020994 0.538303
Run Code Online (Sandbox Code Playgroud)
我希望每个数据帧都有堆积条形图,但由于它们具有相同的索引,我希望每个索引有2个堆叠条形.
我试图在同一轴上绘制两个:
In [5]: ax = df1.plot(kind="bar", stacked=True)
In [5]: ax2 = df2.plot(kind="bar", stacked=True, ax = ax)
Run Code Online (Sandbox Code Playgroud)
但它重叠.
然后我尝试先连接两个数据集:
pd.concat(dict(df1 = df1, df2 = df2),axis = 1).plot(kind="bar", stacked=True)
Run Code Online (Sandbox Code Playgroud)
但这里一切都堆积如山
我最好的尝试是:
pd.concat(dict(df1 = df1, df2 = df2),axis = 0).plot(kind="bar", stacked=True)
Run Code Online (Sandbox Code Playgroud)
这使 :

这基本上是我想要的,除了我想要的酒吧订购
(df1,A)(df2,A)(df1,B)(df2,B)等......
我想有一个技巧,但我找不到它!
在@ bgschiller的回答之后我得到了这个:
这几乎是我想要的.我希望通过索引对条形图进行聚类,以便在视觉上清晰.
额外:x标签不是多余的,如:
df1 df2 df1 df2
_______ _______ ...
A B
Run Code Online (Sandbox Code Playgroud)
谢谢你的帮助.
jrj*_*rjc 61
所以,我最终找到了一个技巧(编辑:请参阅下面的使用seaborn和longform数据帧):
这是一个更完整的例子:
import pandas as pd
import matplotlib.cm as cm
import numpy as np
import matplotlib.pyplot as plt
def plot_clustered_stacked(dfall, labels=None, title="multiple stacked bar plot", H="/", **kwargs):
"""Given a list of dataframes, with identical columns and index, create a clustered stacked bar plot.
labels is a list of the names of the dataframe, used for the legend
title is a string for the title of the plot
H is the hatch used for identification of the different dataframe"""
n_df = len(dfall)
n_col = len(dfall[0].columns)
n_ind = len(dfall[0].index)
axe = plt.subplot(111)
for df in dfall : # for each data frame
axe = df.plot(kind="bar",
linewidth=0,
stacked=True,
ax=axe,
legend=False,
grid=False,
**kwargs) # make bar plots
h,l = axe.get_legend_handles_labels() # get the handles we want to modify
for i in range(0, n_df * n_col, n_col): # len(h) = n_col * n_df
for j, pa in enumerate(h[i:i+n_col]):
for rect in pa.patches: # for each index
rect.set_x(rect.get_x() + 1 / float(n_df + 1) * i / float(n_col))
rect.set_hatch(H * int(i / n_col)) #edited part
rect.set_width(1 / float(n_df + 1))
axe.set_xticks((np.arange(0, 2 * n_ind, 2) + 1 / float(n_df + 1)) / 2.)
axe.set_xticklabels(df.index, rotation = 0)
axe.set_title(title)
# Add invisible data to add another legend
n=[]
for i in range(n_df):
n.append(axe.bar(0, 0, color="gray", hatch=H * i))
l1 = axe.legend(h[:n_col], l[:n_col], loc=[1.01, 0.5])
if labels is not None:
l2 = plt.legend(n, labels, loc=[1.01, 0.1])
axe.add_artist(l1)
return axe
# create fake dataframes
df1 = pd.DataFrame(np.random.rand(4, 5),
index=["A", "B", "C", "D"],
columns=["I", "J", "K", "L", "M"])
df2 = pd.DataFrame(np.random.rand(4, 5),
index=["A", "B", "C", "D"],
columns=["I", "J", "K", "L", "M"])
df3 = pd.DataFrame(np.random.rand(4, 5),
index=["A", "B", "C", "D"],
columns=["I", "J", "K", "L", "M"])
# Then, just call :
plot_clustered_stacked([df1, df2, df3],["df1", "df2", "df3"])
Run Code Online (Sandbox Code Playgroud)
它给出了:

您可以通过传递cmap参数来更改栏的颜色:
plot_clustered_stacked([df1, df2, df3],
["df1", "df2", "df3"],
cmap=plt.cm.viridis)
Run Code Online (Sandbox Code Playgroud)
给定相同的df1,df2,df3,我将它们转换为长形式:
df1["Name"] = "df1"
df2["Name"] = "df2"
df3["Name"] = "df3"
dfall = pd.concat([pd.melt(i.reset_index(),
id_vars=["Name", "index"]) # transform in tidy format each df
for i in [df1, df2, df3]],
ignore_index=True)
Run Code Online (Sandbox Code Playgroud)
seaborn的问题在于它本身不会堆叠条形图,因此诀窍是将每个条形图的累积总和绘制在彼此之上:
dfall.set_index(["Name", "index", "variable"], inplace=1)
dfall["vcs"] = dfall.groupby(level=["Name", "index"]).cumsum()
dfall.reset_index(inplace=True)
>>> dfall.head(6)
Name index variable value vcs
0 df1 A I 0.717286 0.717286
1 df1 B I 0.236867 0.236867
2 df1 C I 0.952557 0.952557
3 df1 D I 0.487995 0.487995
4 df1 A J 0.174489 0.891775
5 df1 B J 0.332001 0.568868
Run Code Online (Sandbox Code Playgroud)
然后循环遍历每组variable并绘制累积总和:
c = ["blue", "purple", "red", "green", "pink"]
for i, g in enumerate(dfall.groupby("variable")):
ax = sns.barplot(data=g[1],
x="index",
y="vcs",
hue="Name",
color=c[i],
zorder=-i, # so first bars stay on top
edgecolor="k")
ax.legend_.remove() # remove the redundant legends
Run Code Online (Sandbox Code Playgroud)
它缺乏我认为可以轻松添加的传奇.问题是,为了区分数据框而不是阴影(可以很容易地添加),我们有一个亮度梯度,而且它对于第一个有点太亮了,我真的不知道如何改变它而不改变每个矩形逐个(如第一个解决方案).
如果你不理解代码中的某些内容,请告诉我.
随意重复使用CC0下的代码.
@jrjc 对 use of 的回答seaborn很聪明,但是有几个问题,作者指出:
然而,更重要的是,我发现,因为groupby代码中的语句:
["I", "J", "K", "L", "M"]用反字母 ( ["zI", "yJ", "xK", "wL", "vM"])重命名列,我会得到这个图:我努力通过这个开源 python 模块中的plot_grouped_stackedbars()函数来解决这些问题。
groupby它还允许
在此处查看完整演示。我希望这证明是有用的,并且可以回答最初的问题。
小智 6
这是Cord Kaldemeyer答案的更简洁的实现。这个想法是为绘图保留尽可能多的宽度。然后每个簇得到所需长度的子图。
# Data and imports
import pandas as pd
import matplotlib.pyplot as plt
import numpy as np
from matplotlib.ticker import MaxNLocator
import matplotlib.gridspec as gridspec
import matplotlib
matplotlib.style.use('ggplot')
np.random.seed(0)
df = pd.DataFrame(np.asarray(1+5*np.random.random((10,4)), dtype=int),columns=["Cluster", "Bar", "Bar_part", "Count"])
df = df.groupby(["Cluster", "Bar", "Bar_part"])["Count"].sum().unstack(fill_value=0)
display(df)
# plotting
clusters = df.index.levels[0]
inter_graph = 0
maxi = np.max(np.sum(df, axis=1))
total_width = len(df)+inter_graph*(len(clusters)-1)
fig = plt.figure(figsize=(total_width,10))
gridspec.GridSpec(1, total_width)
axes=[]
ax_position = 0
for cluster in clusters:
subset = df.loc[cluster]
ax = subset.plot(kind="bar", stacked=True, width=0.8, ax=plt.subplot2grid((1,total_width), (0,ax_position), colspan=len(subset.index)))
axes.append(ax)
ax.set_title(cluster)
ax.set_xlabel("")
ax.set_ylim(0,maxi+1)
ax.yaxis.set_major_locator(MaxNLocator(integer=True))
ax_position += len(subset.index)+inter_graph
for i in range(1,len(clusters)):
axes[i].set_yticklabels("")
axes[i-1].legend().set_visible(False)
axes[0].set_ylabel("y_label")
fig.suptitle('Big Title', fontsize="x-large")
legend = axes[-1].legend(loc='upper right', fontsize=16, framealpha=1).get_frame()
legend.set_linewidth(3)
legend.set_edgecolor("black")
plt.show()
Run Code Online (Sandbox Code Playgroud)
结果如下:
我已经设法通过基本命令使用pandas和matplotlib子图来做同样的事情。
这是一个例子:
fig, axes = plt.subplots(nrows=1, ncols=3)
ax_position = 0
for concept in df.index.get_level_values('concept').unique():
idx = pd.IndexSlice
subset = df.loc[idx[[concept], :],
['cmp_tr_neg_p_wrk', 'exp_tr_pos_p_wrk',
'cmp_p_spot', 'exp_p_spot']]
print(subset.info())
subset = subset.groupby(
subset.index.get_level_values('datetime').year).sum()
subset = subset / 4 # quarter hours
subset = subset / 100 # installed capacity
ax = subset.plot(kind="bar", stacked=True, colormap="Blues",
ax=axes[ax_position])
ax.set_title("Concept \"" + concept + "\"", fontsize=30, alpha=1.0)
ax.set_ylabel("Hours", fontsize=30),
ax.set_xlabel("Concept \"" + concept + "\"", fontsize=30, alpha=0.0),
ax.set_ylim(0, 9000)
ax.set_yticks(range(0, 9000, 1000))
ax.set_yticklabels(labels=range(0, 9000, 1000), rotation=0,
minor=False, fontsize=28)
ax.set_xticklabels(labels=['2012', '2013', '2014'], rotation=0,
minor=False, fontsize=28)
handles, labels = ax.get_legend_handles_labels()
ax.legend(['Market A', 'Market B',
'Market C', 'Market D'],
loc='upper right', fontsize=28)
ax_position += 1
# look "three subplots"
#plt.tight_layout(pad=0.0, w_pad=-8.0, h_pad=0.0)
# look "one plot"
plt.tight_layout(pad=0., w_pad=-16.5, h_pad=0.0)
axes[1].set_ylabel("")
axes[2].set_ylabel("")
axes[1].set_yticklabels("")
axes[2].set_yticklabels("")
axes[0].legend().set_visible(False)
axes[1].legend().set_visible(False)
axes[2].legend(['Market A', 'Market B',
'Market C', 'Market D'],
loc='upper right', fontsize=28)
Run Code Online (Sandbox Code Playgroud)
分组之前“子集”的数据帧结构如下所示:
<class 'pandas.core.frame.DataFrame'>
MultiIndex: 105216 entries, (D_REC, 2012-01-01 00:00:00) to (D_REC, 2014-12-31 23:45:00)
Data columns (total 4 columns):
cmp_tr_neg_p_wrk 105216 non-null float64
exp_tr_pos_p_wrk 105216 non-null float64
cmp_p_spot 105216 non-null float64
exp_p_spot 105216 non-null float64
dtypes: float64(4)
memory usage: 4.0+ MB
Run Code Online (Sandbox Code Playgroud)
和这样的情节:
它的格式为“ ggplot”,带有以下标头:
import pandas as pd
import matplotlib.pyplot as plt
import matplotlib
matplotlib.style.use('ggplot')
Run Code Online (Sandbox Code Playgroud)
这是一个很好的开始,但我认为可以对颜色进行一些修改以使其更加清晰。另外,在导入Altair中的每个参数时也要小心,因为这可能导致与命名空间中的现有对象发生冲突。这是一些重新配置的代码,用于在堆叠值时显示正确的颜色显示:
import pandas as pd
import numpy as np
import altair as alt
Run Code Online (Sandbox Code Playgroud)
df1=pd.DataFrame(10*np.random.rand(4,3),index=["A","B","C","D"],columns=["I","J","K"])
df2=pd.DataFrame(10*np.random.rand(4,3),index=["A","B","C","D"],columns=["I","J","K"])
df3=pd.DataFrame(10*np.random.rand(4,3),index=["A","B","C","D"],columns=["I","J","K"])
def prep_df(df, name):
df = df.stack().reset_index()
df.columns = ['c1', 'c2', 'values']
df['DF'] = name
return df
df1 = prep_df(df1, 'DF1')
df2 = prep_df(df2, 'DF2')
df3 = prep_df(df3, 'DF3')
df = pd.concat([df1, df2, df3])
Run Code Online (Sandbox Code Playgroud)
alt.Chart(df).mark_bar().encode(
# tell Altair which field to group columns on
x=alt.X('c2:N', title=None),
# tell Altair which field to use as Y values and how to calculate
y=alt.Y('sum(values):Q',
axis=alt.Axis(
grid=False,
title=None)),
# tell Altair which field to use to use as the set of columns to be represented in each group
column=alt.Column('c1:N', title=None),
# tell Altair which field to use for color segmentation
color=alt.Color('DF:N',
scale=alt.Scale(
# make it look pretty with an enjoyable color pallet
range=['#96ceb4', '#ffcc5c','#ff6f69'],
),
))\
.configure_view(
# remove grid lines around column clusters
strokeOpacity=0
)
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
25718 次 |
| 最近记录: |