jho*_*and 0 opengl qt texture-mapping
我试图将图像纹理映射到单个多边形.我的图像正在被正确读取,但只有图像的红色平面被纹理化.
我在QGLWidget中这样做
我在读完后检查了图像,并且正在正确读取组件 - 即,我得到绿色和蓝色平面的有效值.
这是代码
QImageReader *theReader = new QImageReader();
theReader->setFileName(imageFileName);
QImage theImageRead = theReader->read();
if(theImageRead.isNull())
{
validTile = NOT_VALID_IMAGE_FILE;
return;
}
else
{
int newW = 1;
int newH = 1;
while(newW < theImageRead.width())
{
newW *= 2;
}
while(newH < theImageRead.height())
{
newH *= 2;
}
theImageRead = theImageRead.scaled(newW, newH, Qt::IgnoreAspectRatio, Qt::SmoothTransformation);
// values checked in theImageRead are OK here
glGenTextures(1,&textureObject);
theTextureImage = QGLWidget::convertToGLFormat(theImageRead);
// values checked in theTextureImage are OK here
glBindTexture(GL_TEXTURE_2D, textureObject);
glTexImage2D(GL_TEXTURE_2D,0,GL_RGB,newW, newH, 0, GL_RGBA, GL_UNSIGNED_BYTE,theTextureImage.bits() );
glTexParameteri(GL_TEXTURE_2D,GL_TEXTURE_MIN_FILTER, GL_LINEAR);
glFlush();
validTile = VALID_TEXTURE;
return;
}
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then I draw like this:
{
glEnable(GL_TEXTURE_2D);
glBindTexture(GL_TEXTURE_2D,textureTiles[tN]->getTextureObject() );
glBegin(GL_QUADS);
glTexCoord2f(0.0,0.0);
glVertex2f(textureTiles[tN]->lowerLeft.x(), textureTiles[tN]->lowerLeft.y());
glTexCoord2f(1.0,0.0);
glVertex2f(textureTiles[tN]->lowerRight.x(), textureTiles[tN]->lowerRight.y());
glTexCoord2f(1.0,1.0);
glVertex2f(textureTiles[tN]->upperRight.x(), textureTiles[tN]->upperRight.y());
glTexCoord2f(0.0,1.0);
glVertex2f(textureTiles[tN]->upperLeft.x(), textureTiles[tN]->upperLeft.y());
glEnd();
glDisable(GL_TEXTURE_2D);
}
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有没有人看到任何会导致我的纹理被解释的东西,好像它是(r,0,0,1)的值?(R,G,B,A)?
QT 4.7.1,Ubuntu 10.04,openGl 2.something或其他
提前感谢您的帮助
我有类似的问题.我发现在绘制纹理四边形之前我必须将gl颜色"重置"为白色和不透明,否则颜色会变得混乱.像这样:
...
glEnable(GL_TEXTURE_2D);
glBindTexture(GL_TEXTURE_2D,textureTiles[tN]->getTextureObject() );
glColor4f(1.0, 1.0, 1.0, 1.0); // reset gl color
glBegin(GL_QUADS);
...
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