删除所有列中具有相同值的行

Question

假设我有一个如下所示的数据框(df):

options(stringsAsFactors = F)

cars <- c("Car1", "Car2", "Car3", "Car4", "Car5", "Car6", "Car7", "Car8", "Car9")
test1 <- c(0,0,3,1,4,2,1,3,0)
test2 <- c(0,0,2,1,0,2,2,5,0)
test3 <- c(1,0,5,1,2,2,6,7,0)
test4 <- c(2,NA,2,1,2,2,1,1,0)
test5 <- c(0,0,1,1,0,2,1,3,0)
test6 <- c(1,0,1,1,1,2,3,4,0)
test7 <- c(3,0,2,1,0,2,1,1,0)

df <- data.frame(cars,test1,test2,test3,test4,test5,test6,test7)

#df
   cars test1 test2 test3 test4 test5 test6 test7
#1 Car1     0     0     1     2     0     1     3
#2 Car2     0     0     0    NA     0     0     0
#3 Car3     3     2     5     2     1     1     2
#4 Car4     1     1     1     1     1     1     1
#5 Car5     4     0     2     2     0     1     0
#6 Car6     2     2     2     2     2     2     2
#7 Car7     1     2     6     1     1     3     1
#8 Car8     3     5     7     1     3     4     1
#9 Car9     0     0     0     0     0     0     0

我想删除整个行中具有相同值的任何行(在上面的示例中,我想保留行1,3,5,7,8并删除其余行).

我已经想出如何删除所有有零的行

 df$sum <- rowSums(df[,c(2:8)], na.rm = T )
 df.all0 <- df[which(df$sum == 0),]

但是,这并不一定适用于所有其他行.与其他问题不同,此问题要求在整个行中查找重复项,而不仅仅是特定列.

任何帮助将不胜感激!

Answer 1

keep <- apply(df[2:8], 1, function(x) length(unique(x[!is.na(x)])) != 1)
df[keep, ]

  cars test1 test2 test3 test4 test5 test6 test7
1 Car1     0     0     1     2     0     1     3
3 Car3     3     2     5     2     1     1     2
5 Car5     4     0     2     2     0     1     0
7 Car7     1     2     6     1     1     3     1
8 Car8     3     5     7     1     3     4     1

Answer 2

这是一个选项rowSums; 逻辑是从您感兴趣的列中检查行中是否有任何值(NA不计数):

df[rowSums(df[-1] != df[[2]], na.rm = TRUE) != 0,]

#  cars test1 test2 test3 test4 test5 test6 test7
#1 Car1     0     0     1     2     0     1     3
#3 Car3     3     2     5     2     1     1     2
#5 Car5     4     0     2     2     0     1     0
#7 Car7     1     2     6     1     1     3     1
#8 Car8     3     5     7     1     3     4     1