使用FindWindow()时如何跳过隐藏的窗口？

Question

我没有显示它创建一个窗口:

int main()
{
    CreateWindow("SysListView32","Geek",0, 0, 0, 0, 0,NULL, NULL, (HINSTANCE)GetCurrentProcess(), NULL);

    getch();
}

...并在另一个进程中用于FindWindow()查找其句柄:

int main()
{
    HWND H = FindWindow("SysListView32", "Geek");
    std::cout<< "The handle of created window is : " <<H;

    getch();
}

怎么FindWindow找到它的手柄？我以为它不会找到它,因为process1没有显示窗口.

我怎样才能找到可见的窗户？

Answer 1

即使窗口不可见,它当然也在FindWindow枚举的所有现有窗口的列表中(例如,您可以使用Spy ++显示此列表).如果您不想搜索隐藏的窗口,则必须检查其标志:

HWND H = FindWindow("SysListView32", "Geek");
if (H)  {
  LONG style = GetWindowLong(H, GWL_STYLE);
  if (style & WS_VISIBLE)
    std::cout << "The handle of created visible window is : " << H << std::endl;
  else
    std::cout << "The handle of created hidden window is : " << H << std::endl;
} else {
  std::cout << "No such window found" << std::endl;
}