hks*_*014 10 python numpy keras
import numpy as np
from keras.utils import np_utils
nsample = 100
sample_space = ["HOME","DRAW","AWAY"]
array = np.random.choice(sample_space, nsample, )
uniques, coded_id = np.unique(array, return_inverse=True)
coded_array = np_utils.to_categorical(coded_id)
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例
映射字典
['AWAY', 'HOME', 'DRAW', 'AWAY', ...]
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输入
[[ 0. 1. 0.]
[ 0. 0. 1.]
[ 0. 0. 1.]
...,
[ 0. 0. 1.]
[ 0. 0. 1.]
[ 1. 0. 0.]]
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编码输出
import numpy as np
from keras.utils import np_utils
nsample = 100
sample_space = ["HOME","DRAW","AWAY"]
array = np.random.choice(sample_space, nsample, )
uniques, coded_id = np.unique(array, return_inverse=True)
coded_array = np_utils.to_categorical(coded_id)
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如何反转此功能并获得解码功能?
Div*_*kar 13
您可以使用它np.argmax来检索那些ids,然后简单地索引到uniques应该给你原始数组.因此,我们会有一个实现,就像这样 -
uniques[y_code.argmax(1)]
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样品运行 -
In [44]: arr
Out[44]: array([5, 7, 3, 2, 4, 3, 7])
In [45]: uniques, ids = np.unique(arr, return_inverse=True)
In [46]: y_code = np_utils.to_categorical(ids, len(uniques))
In [47]: uniques[y_code.argmax(1)]
Out[47]: array([5, 7, 3, 2, 4, 3, 7])
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