Ian*_*ica 8 python unix python-2.7 python-multiprocessing
我正在进行python mutliprocessing模块的第一次尝试,我遇到了一些问题.我对线程模块非常熟悉,但我需要确保我正在执行的进程并行运行.
这是我正在尝试做的概述.请忽略未声明的变量/函数之类的内容,因为我无法完全粘贴代码.
import multiprocessing
import time
def wrap_func_to_run(host, args, output):
output.append(do_something(host, args))
return
def func_to_run(host, args):
return do_something(host, args)
def do_work(server, client, server_args, client_args):
server_output = func_to_run(server, server_args)
client_output = func_to_run(client, client_args)
#handle this output and return a result
return result
def run_server_client(server, client, server_args, client_args, server_output, client_output):
server_process = multiprocessing.Process(target=wrap_func_to_run, args=(server, server_args, server_output))
server_process.start()
client_process = multiprocessing.Process(target=wrap_func_to_run, args=(client, client_args, client_output))
client_process.start()
server_process.join()
client_process.join()
#handle the output and return some result
def run_in_parallel(server, client):
#set up commands for first process
server_output = client_output = []
server_cmd = "cmd"
client_cmd = "cmd"
process_one = multiprocessing.Process(target=run_server_client, args=(server, client, server_cmd, client_cmd, server_output, client_output))
process_one.start()
#set up second process to run - but this one can run here
result = do_work(server, client, "some server args", "some client args")
process_one.join()
#use outputs above and the result to determine result
return final_result
def main():
#grab client
client = client()
#grab server
server = server()
return run_in_parallel(server, client)
if __name__ == "__main__":
main()
Run Code Online (Sandbox Code Playgroud)
这是我得到的错误:
Error in sys.exitfunc:
Traceback (most recent call last):
File "/usr/lib64/python2.7/atexit.py", line 24, in _run_exitfuncs
func(*targs, **kargs)
File "/usr/lib64/python2.7/multiprocessing/util.py", line 319, in _exit_function
p.join()
File "/usr/lib64/python2.7/multiprocessing/process.py", line 143, in join
assert self._parent_pid == os.getpid(), 'can only join a child process'
AssertionError: can only join a child process
Run Code Online (Sandbox Code Playgroud)
我已经尝试了很多不同的东西来解决这个问题,但我的感觉是我使用这个模块的方式有问题.
编辑:
所以我创建了一个文件,通过模拟客户端/服务器和他们的工作来重现这一点 - 我也错过了一个重要的观点,那就是我在unix中运行它.另一个重要的信息是,do_work在我的实际案例中涉及使用os.fork().没有使用我无法重现错误,os.fork()所以我假设问题存在.在我的真实案例中,代码的那部分不是我的,所以我把它当成黑盒子(可能是我的错误).无论如何这里是重现的代码 -
#!/usr/bin/python
import multiprocessing
import time
import os
import signal
import sys
class Host():
def __init__(self):
self.name = "host"
def work(self):
#override - use to simulate work
pass
class Server(Host):
def __init__(self):
self.name = "server"
def work(self):
x = 0
for i in range(10000):
x+=1
print x
time.sleep(1)
class Client(Host):
def __init__(self):
self.name = "client"
def work(self):
x = 0
for i in range(5000):
x+=1
print x
time.sleep(1)
def func_to_run(host, args):
print host.name + " is working"
host.work()
print host.name + ": " + args
return "done"
def do_work(server, client, server_args, client_args):
print "in do_work"
server_output = client_output = ""
child_pid = os.fork()
if child_pid == 0:
server_output = func_to_run(server, server_args)
sys.exit(server_output)
time.sleep(1)
client_output = func_to_run(client, client_args)
# kill and wait for server to finish
os.kill(child_pid, signal.SIGTERM)
(pid, status) = os.waitpid(child_pid, 0)
return (server_output == "done" and client_output =="done")
def run_server_client(server, client, server_args, client_args):
server_process = multiprocessing.Process(target=func_to_run, args=(server, server_args))
print "Starting server process"
server_process.start()
client_process = multiprocessing.Process(target=func_to_run, args=(client, client_args))
print "Starting client process"
client_process.start()
print "joining processes"
server_process.join()
client_process.join()
print "processes joined and done"
def run_in_parallel(server, client):
#set up commands for first process
server_cmd = "server command for run_server_client"
client_cmd = "client command for run_server_client"
process_one = multiprocessing.Process(target=run_server_client, args=(server, client, server_cmd, client_cmd))
print "Starting process one"
process_one.start()
#set up second process to run - but this one can run here
print "About to do work"
result = do_work(server, client, "server args from do work", "client args from do work")
print "Joining process one"
process_one.join()
#use outputs above and the result to determine result
print "Process one has joined"
return result
def main():
#grab client
client = Client()
#grab server
server = Server()
return run_in_parallel(server, client)
if __name__ == "__main__":
main()
Run Code Online (Sandbox Code Playgroud)
如果我删除os.fork()in in 的使用do_work我没有得到错误,代码的行为就像我之前预期的那样(除了输出我已经接受的错误/误解).我可以将旧代码更改为不使用os.fork(),但我也想知道为什么会导致这个问题以及是否有可行的解决方案.
编辑2:
我开始研究一个在接受的答案之前省略os.fork()的解决方案.这就是我对可以完成的模拟工作量的调整 -
#!/usr/bin/python
import multiprocessing
import time
import os
import signal
import sys
from Queue import Empty
class Host():
def __init__(self):
self.name = "host"
def work(self, w):
#override - use to simulate work
pass
class Server(Host):
def __init__(self):
self.name = "server"
def work(self, w):
x = 0
for i in range(w):
x+=1
print x
time.sleep(1)
class Client(Host):
def __init__(self):
self.name = "client"
def work(self, w):
x = 0
for i in range(w):
x+=1
print x
time.sleep(1)
def func_to_run(host, args, w, q):
print host.name + " is working"
host.work(w)
print host.name + ": " + args
q.put("ZERO")
return "done"
def handle_queue(queue):
done = False
results = []
return_val = 0
while not done:
#try to grab item from Queue
tr = None
try:
tr = queue.get_nowait()
print "found element in queue"
print tr
except Empty:
done = True
if tr is not None:
results.append(tr)
for el in results:
if el != "ZERO":
return_val = 1
return return_val
def do_work(server, client, server_args, client_args):
print "in do_work"
server_output = client_output = ""
child_pid = os.fork()
if child_pid == 0:
server_output = func_to_run(server, server_args)
sys.exit(server_output)
time.sleep(1)
client_output = func_to_run(client, client_args)
# kill and wait for server to finish
os.kill(child_pid, signal.SIGTERM)
(pid, status) = os.waitpid(child_pid, 0)
return (server_output == "done" and client_output =="done")
def run_server_client(server, client, server_args, client_args, w, mq):
local_queue = multiprocessing.Queue()
server_process = multiprocessing.Process(target=func_to_run, args=(server, server_args, w, local_queue))
print "Starting server process"
server_process.start()
client_process = multiprocessing.Process(target=func_to_run, args=(client, client_args, w, local_queue))
print "Starting client process"
client_process.start()
print "joining processes"
server_process.join()
client_process.join()
print "processes joined and done"
if handle_queue(local_queue) == 0:
mq.put("ZERO")
def run_in_parallel(server, client):
#set up commands for first process
master_queue = multiprocessing.Queue()
server_cmd = "server command for run_server_client"
client_cmd = "client command for run_server_client"
process_one = multiprocessing.Process(target=run_server_client, args=(server, client, server_cmd, client_cmd, 400000000, master_queue))
print "Starting process one"
process_one.start()
#set up second process to run - but this one can run here
print "About to do work"
#result = do_work(server, client, "server args from do work", "client args from do work")
run_server_client(server, client, "server args from do work", "client args from do work", 5000, master_queue)
print "Joining process one"
process_one.join()
#use outputs above and the result to determine result
print "Process one has joined"
return_val = handle_queue(master_queue)
print return_val
return return_val
def main():
#grab client
client = Client()
#grab server
server = Server()
val = run_in_parallel(server, client)
if val:
print "failed"
else:
print "passed"
return val
if __name__ == "__main__":
main()
Run Code Online (Sandbox Code Playgroud)
这段代码有一些调整后的打印输出,只是为了看看到底发生了什么.我使用了multiprocessing.Queue来存储和共享进程中的输出,然后返回到我要处理的主线程中.我认为这解决了我的问题的python部分,但我正在处理的代码中仍然存在一些问题.我唯一可以说的是,相当于func_to_run涉及通过ssh发送命令并抓住任何错误以及输出.出于某种原因,这对于执行时间较短的命令非常适用,但对于具有大得多的执行时间/输出的命令则不太好.我试着在我的代码中使用截然不同的工作值来模拟这个,但是无法重现类似的结果.
编辑3我正在使用的库代码(再次不是我的)Popen.wait()用于ssh命令,我只读了这个:
Popen.wait()等待子进程终止.设置并返回returncode属性.警告当使用stdout = PIPE和/或stderr = PIPE时,这将导致死锁,并且>子进程会为管道生成足够的输出,以便阻止等待> OS管道缓冲区接受更多数据.使用communic()来避免这种情况.
我将代码调整为不缓冲,只是在接收时打印,一切正常.
我可以将旧代码更改为不使用
os.fork(),但我也想知道为什么会导致此问题以及是否有可行的解决方案。
理解问题的关键是准确地了解问题fork()所在。CPython 文档声明“分叉子进程”。但这假设您了解 C 库调用fork()。
以下是 glibc 的联机帮助页对此的说明:
fork()通过复制调用进程来创建一个新进程。新进程(称为子进程)与调用进程(称为父进程)完全相同,但以下几点除外:...
基本上就好像您获取了程序并制作了其程序状态(堆、堆栈、指令指针等)的副本(有一些细微的差异),并让它独立于原始程序执行。当这个子进程自然退出时,它将使用exit()和 ,这将触发模块atexit()注册的处理程序multiprocessing。
你可以做什么来避免它?
os.fork():multiprocessing改为使用,就像您现在正在探索的那样import multiprocessing执行后fork(),仅在必要时在子级或父级中有效。_exit()(CPython 文档声明,“注意退出的标准方法是 sys.exit(n)。_exit() 通常只应在 fork() 之后的子进程中使用。”)https://docs.python.org/2/library/os.html#os._exit
| 归档时间: |
|
| 查看次数: |
5734 次 |
| 最近记录: |