Tim*_*Tim 100

您可以bounds在UIScreen的实例上使用该属性:

CGRect screenBound = [[UIScreen mainScreen] bounds];
CGSize screenSize = screenBound.size;  
CGFloat screenWidth = screenSize.width;
CGFloat screenHeight = screenSize.height;
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大多数人都想要主屏幕; 如果你有一台设备连接到电视,你可能想要迭代UIScreens并获得每个设备的界限.

有关UIScreen类文档的更多信息.


mog*_*ter 22

这是一个'迅捷'的解决方案:(更新为swift 3.x)

let screenWidth  = UIScreen.main.fixedCoordinateSpace.bounds.width
let screenHeight = UIScreen.main.fixedCoordinateSpace.bounds.height
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这会以点为单位报告,并且"始终以纵向方向反映设备的屏幕尺寸" (Apple Docs).无需烦恼UIAnnoyinglyLongDeviceOrientation!

如果您希望宽度和高度反映设备方向:

let screenWidth  = UIScreen.main.bounds.width
let screenHeight = UIScreen.main.bounds.height
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这里宽度和高度将根据屏幕是纵向还是横向显示翻转值.

以下是如何以像素为单位测量屏幕尺寸而不是点:

let screenWidthInPixels = UIScreen.main.nativeBounds.width
let screenHeightInPixels = UIScreen.main.nativeBounds.height
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这也"基于设备的纵向向上.该值不会随着设备的旋转而改变." (Apple Docs)

请注意,对于swift 2.x及更低版本,您应该使用UIScreen.mainScreen()而不是UIScreen.main


Gur*_*uru 8

使用此代码修复iOS8:

float SW;
float SH;
UIInterfaceOrientation orientation = [UIApplication sharedApplication].statusBarOrientation;
if (( [[[UIDevice currentDevice] systemVersion] floatValue]<8)  && UIInterfaceOrientationIsLandscape(orientation))
{
    SW = [[UIScreen mainScreen] bounds].size.height;
    SH = [[UIScreen mainScreen] bounds].size.width;
}
else
{
    SW = [[UIScreen mainScreen] bounds].size.width;
    SH = [[UIScreen mainScreen] bounds].size.height;
}
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