我试图从1月到12月3次创建一个月的序列.即.1月2月3月 ...12月1月2月3月....12月1月2月3月....十二月
我试过这段代码
rep(c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sept","Oct","Nov","Dec"),each=3)
Run Code Online (Sandbox Code Playgroud)
但它会产生这样的结果
[1] "Jan" "Jan" "Jan" "Feb" "Feb" "Feb" "Mar" "Mar" "Mar" "Apr" "Apr" "Apr"
[13] "May" "May" "May" "Jun" "Jun" "Jun" "Jul" "Jul" "Jul" "Aug" "Aug" "Aug"
[25] "Sept" "Sept" "Sept" "Oct" "Oct" "Oct" "Nov" "Nov" "Nov" "Dec" "Dec" "Dec"
Run Code Online (Sandbox Code Playgroud)
但我想要Jan Feb Mar .... Dec Jan Feb Mar ..... Dec Jan Feb Mar ... Dec
谢谢Harshad
我们可以使用month.abb代替c('Jan', 'Feb')等.
rep(month.abb, 3)
Run Code Online (Sandbox Code Playgroud)
全月名称
rep(month.name, 3)
Run Code Online (Sandbox Code Playgroud)