PHP - 查找数组元素是奇数还是偶数

Question

我有一系列这样的项目：

$data = array(
            'item1' => array( // is even
                'icon' => 'commenting',
                'content' => 'Lorem ipsum dolor sit amet, consectetur adipisicing elit. ',
            ), 
            'item2' => array(// is odd
                'icon' => 'sticky-note',
                'content' => 'Debitis id eligendi assumenda, cumque optio veniam eos perferendis molestias explicabo odit',
            ),
            'item3' => array(// is even
                'icon' => 'users',
                'content' => 'Libero, suscipit, quos. Quae praesentium tempore minima quod tempora odio',
            ),
            'item4' => array(// is odd
                'icon' => 'thumbs-o-up',
                'content' => 'Lorem ipsum dolor sit amet, consectetur adipisicing elit. ',
            ),
            'item5' => array(// is even
                'icon' => 'wrench',
                'content' => 'Debitis id eligendi assumenda, cumque optio veniam eos perferendis molestias explicabo odi',
            ),
        );

我想要做的是，当我遍历数组的元素以输出它们时，检测每个元素是奇数还是偶数，例如：

foreach ($data as $key => $value) {
    echo '<h1>' . $key . '</h1>';
    echo '<p>' . $value['icon'] . '</p>';
    echo '<p>' . $value['content'] . '</p>';
    echo '<p> (Item is odd or even) </p>'; // * Show wheather is odd or even here
}

Answer 1

只需声明一个计数器并迭代即可。

$counter = 1;
foreach ($data as $key => $value) {
    echo '<h1>' . $key . '</h1>';
    echo '<p>' . $value['icon'] . '</p>';
    echo '<p>' . $value['content'] . '</p>';
    echo '<p> ' . (($counter % 2)? 'odd': 'even') . ' </p>'; // * Show whether the position is odd or even here
    $counter++;
}