如何统一检查位是否设置为无符号整数？

Question

给定无符号整数,我想知道是否有办法确定是否在单个操作中设置了多个位.已经有一种替代方法可以通过逐位检查来实现这一点(如下所示),但我想知道是否有办法集中检查所有位.

typedef enum Foo_X
{
  Foo_0 = 0x1,
  Foo_1 = 0x2,
  Foo_2 = 0x4,
  Foo_3 = 0x8,
} Foo_X;

bool CheckFoo ( UINT Value, Foo_X Foo_to_Check )
{
    if (Value & Foo_to_Check)
    {
        // Foo_to_Check is present
        return true;
    }
}

void main()
{
    UINT value = GetValueFromSomewhere();
    if (CheckFoo(value, Foo_0) && CheckFoo(value, Foo_3))
        // both Foo_0 and Foo_3 are present
    else
        // not both present
}

使用集合方法的示例也如下所示.有任何想法吗？TIA!

bool CheckFooTogether ( UINT Value, UINT Foos_to_Check )
{
    // check value against Foos_to_Check collectively
}

void main()
{
    UINT value = GetValueFromSomewhere();
    if (CheckFooTogether (value, Foo_0 | Foo_3))
        // both Foo_0 and Foo_3 are present
    else
        // not both present           
}

Answer 1

(Value&Foos_to_Check)== Foos_to_Check