将开始和结束坐标转换为R中的空间线

Question

我有一组开始和结束坐标,如下所示:

begin.coord <- data.frame(lon=c(-85.76,-85.46,-85.89), lat=c(38.34,38.76,38.31))
end.coord <- data.frame(lon=c(-85.72,-85.42,-85.85), lat=c(38.38,38.76,38.32))

我试图通过将每个起点连接到其对应的终点来创建一组3个线段.我希望最终产品成为一个SpatialLines对象,以便我可以over在sp包中使用它.

Answer 1

这是一种方式:

## raw list to store Lines objects
l <- vector("list", nrow(begin.coord))
library(sp)
for (i in seq_along(l)) {
    l[[i]] <- Lines(list(Line(rbind(begin.coord[i, ], end.coord[i,]))), as.character(i))
}

SpatialLines(l)

这会为每对创建一个单独的Lines对象(每个对象都有一个唯一的ID),否则您可能想要一个对象？

只是为了好玩,首先构建为spatstat psp对象,然后强制使用maptools中的方法:

library(spatstat)
p <- psp(begin.coord[,1], begin.coord[,2], end.coord[,1], end.coord[,2],     owin(range(c(begin.coord[,1], end.coord[,1])), range(c(begin.coord[,2], end.coord[,2]))))

library(maptools)
as(p, "SpatialLines") 

Answer 2

还可以使用sf包来构建sfc类列表，然后将其转换为SpatialLines对象：

# the given data
begin.coord <- data.frame(lon=c(-85.76,-85.46,-85.89), lat=c(38.34,38.76,38.31))
end.coord <- data.frame(lon=c(-85.72,-85.42,-85.85), lat=c(38.38,38.76,38.32))

library(sf)

# Create list of simple feature geometries (linestrings)
l_sf <- vector("list", nrow(begin.coord))
for (i in seq_along(l_sf)){
  l_sf[[i]] <- st_linestring(as.matrix(rbind(begin.coord[i, ], end.coord[i,])))
}
# Create simple feature geometry list column
l_sfc <- st_sfc(l_sf, crs = "+proj=longlat +datum=WGS84")

# Convert to `sp` object if needed
lines_sp <- as(l_sfc, "Spatial")

额外/可选：

# - create a sf object from the `sfc` list of linestrings
lines_sf = st_sf(id = 1:3, geometry = l_sfc)
# - visualize the `sfc` list of linestrings
plot(l_sfc)
library(mapview)
mapview(l_sfc, lwd = 5) 
# or mapview(lines_sp, lwd = 5)
# or mapview(lines_sf, lwd = 5)