比较值不是相同顺序的两个数组

Question

有没有一种快速的方法来做这样的事情比较两个具有相同值但在PHP中具有不同顺序的数组？

我的数组可能具有相同的数据,但顺序不同,我只需看看它们是否相同.

好吧,事实证明我得到一个对象而不是一个数组,我猜...

object(Doctrine\ORM\PersistentCollection)#560 (9) etc.

嗯...最容易的方法是迭代集合的内容,以便创建我自己的数组然后像你们所建议的那样进行比较？

只需为我的最终解决方案添加代码

        //Find out if container receives mediasync
        $toSync = array();
        foreach($c->getVideosToSync() as $v) {
            $toSync[] = $v->getId();
        }

        $inSync = array();
        foreach($c->getVideosInSync() as $v) {
            $inSync[] = $v->getId();
        }

        $noDiff = array_diff($toSync, $inSync);
        $sameLength = count($toSync) === count($inSync);

        if( empty($noDiff) && $sameLength ) {
           $containerHelper[$c->getId()]['syncing'] = false;
        }
        else {
            $containerHelper[$c->getId()]['syncing'] = true;    
        }

Answer 1

只需使用 & 使它们按统一顺序排列，sort()然后使用 与它们进行比较array_diff()。

# Set the test data.
$array1 = array(1,2,3,4,9,10,11);
$array2 = array(3,4,2,6,7);

# Copy the arrays into new arrays for sorting/testing.
$array1_sort = $array1;
$array2_sort = $array2;

# Sort the arrays.
sort($array1_sort);
sort($array2_sort);

# Diff the sorted arrays.
$array_diff = array_diff($array1_sort, $array2_sort);

# Check if the arrays are the same length or not.
$length_diff = (count($array1) - count($array2));
$DIFFERENT_LENGTH = ($length_diff != 0) ? true : false;

# Check if the arrays are different.
$ARE_THEY_DIFFERENT = ($array_diff > 1) ? true : false;

if ($DIFFERENT_LENGTH) {
  echo 'The are different in length: ' . $length_diff;
}
else {
  echo 'They have the same length.';
}
echo '<br />';

if ($ARE_THEY_DIFFERENT) {
  echo 'They are different: ' . implode(', ', $array_diff);
}
else {
  echo 'They are not different.';
}
echo '<br />';