比较PHP中的数组,而不关心订单

Question

我有两个数组,$ a和$ b,需要检查它们是否包含完全相同的元素(与顺序无关).我正在考虑使用

if (sizeof($a)==sizeof($b) AND array_diff($a,$b)==array())
{

}

但我是PHP的新手,所以我想知道:有更好的方法吗？

因为我需要将它们用作集合,所以我可能根本不应该使用数组而是其他东西.

Answer 1

好吧,我们可以这样做:

if (count(array_diff(array_merge($a, $b), array_intersect($a, $b))) === 0) {
    //they are the same!
}

它的工作原理的原因,是array_merge会带来很大的阵列上,双方的所有元素$a和$b(即是在任的所有元素$a,$b或两者). array_intersect将创建具有所有处于两个元件的阵列$a和$b只.因此,如果它们不同,则必须至少有一个元素不会出现在两个数组中......

另请注意,这sizeof不是实际的函数/构造,它是别名.count()为了清楚起见,我建议使用...

Answer 2

接受的答案是错的!它将失败:https://3v4l.org/U8U5p

$a = ['x' => 1, 'y' => 2]; $b = ['x' => 1, 'y' => 1];

这是一个正确的解决方案:

function consistsOfTheSameValues(array $a, array $b)
{
    // check size of both arrays
    if (count($a) !== count($b)) {
        return false;
    }

    foreach ($b as $key => $bValue) {

        // check that expected value exists in the array
        if (!in_array($bValue, $a, true)) {
            return false;
        }

        // check that expected value occurs the same amount of times in both arrays
        if (count(array_keys($a, $bValue, true)) !== count(array_keys($b, $bValue, true))) {
            return false;
        }

    }

    return true;
}

加上相当广泛的单元测试:https://3v4l.org/m6lHv

<?php

// A unit testing framework in a tweet. https://gist.github.com/mathiasverraes/9046427
function it($m,$p){echo ($p?'??':'?')." It $m\n"; if(!$p){$GLOBALS['f']=1;}}function done(){if(@$GLOBALS['f'])die(1);}

function consistsOfTheSameValues(array $a, array $b)
{
    // check size of both arrays
    if (count($a) !== count($b)) {
        return false;
    }

    foreach ($b as $key => $bValue) {

        // check that expected value exists in the array
        if (!in_array($bValue, $a, true)) {
            return false;
        }

        // check that expected value occurs the same amount of times in both arrays
        if (count(array_keys($a, $bValue, true)) !== count(array_keys($b, $bValue, true))) {
            return false;
        }

    }

    return true;
}

it('consist of the same values',
    consistsOfTheSameValues([1], [1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues([1, 1], [1, 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['1', 1], ['1', 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['1', 1], [1, '1']) === true
);

it('consist of the same values',
    consistsOfTheSameValues([1, '1'], ['1', 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues([1, '1'], [1, '1']) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['x' => 1], ['x' => 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['x' => 1], ['y' => 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['y' => 1], ['x' => 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['x' => 1, 'y' => 1], ['x' => 1, 'y' => 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['y' => 1, 'x' => 1], ['x' => 1, 'y' => 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['x' => 1, 'y' => 1], ['y' => 1, 'x' => 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['y' => 1, 'x' => 1], ['y' => 1, 'x' => 1]) === true
);

it('consist of the same values',
    consistsOfTheSameValues(['x' => 2, 'y' => 1], ['x' => 1, 'y' => 2]) === true
);

it('does not consist of the same values',
    consistsOfTheSameValues([1], [2]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['1'], [1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues([1], ['1']) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues([1], [1, 1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues([1, 1], [1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['1', 1], [1, 1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues([1, '1'], [1, 1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues([1, 1], ['1', 1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues([1, 1], [1, '1']) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['1', '1'], [1, 1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['1', '1'], ['1', 1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['1', '1'], [1, '1']) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues([1, 1], ['1', '1']) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['1', 1], ['1', '1']) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues([1, '1'], ['1', '1']) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['x' => 1], ['x' => 2]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['x' => 1, 'y' => 1], ['x' => 1, 'y' => 2]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['x' => 1, 'y' => 1], ['x' => 2, 'y' => 1]) === false
);

it('does not consist of the same values',
    consistsOfTheSameValues(['x' => 2, 'y' => 1], ['x' => 1, 'y' => 1]) === false
);

@Update:

@ircmaxell的广泛单元测试答案:https://3v4l.org/5ivgm

@Jon anwser的广泛单元测试:https://3v4l.org/CrTgQ

Answer 3

接受的答案无法说明重复项。这是我的

public function sameElements($a, $b)
{
   sort($a);
   sort($b);
   return $a == $b;
}