Kry*_*ian 0 t-sql sql-server-2008
我在我的一个PHP应用程序中使用了这个查询:
SELECT DictSchemeName.schemeName, DictTableName.tableName
FROM DictSchemeName, DictTableName
WHERE DictSchemeName.Id = (SELECT schemeName
FROM ServiceSublayer
WHERE sId = 3
AND ServiceId = (SELECT Id
FROM Service
WHERE applicationId = 'prga'))
AND DictTableName.Id = (SELECT tableName
FROM ServiceSublayer
WHERE sId = 3
AND ServiceId =(SELECT Id
FROM Service
WHERE applicationId = 'prga'));
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正如你所看到的那样,我将两次几乎相同的查询加倍(DictSchemeName和DictTableName),我开始学习SQL,如果有人能帮助我,我会很高兴.
我正在使用MS SQL SERVER 2008
你应该能够加入表格:
select ds.schemeName,
dt.tableName
from
(
select schemeName, tableName
from ServiceSublayer
where sId = 3
and ServiceId = (SELECT Id
FROM Service
WHERE applicationId = 'prga')
) s
inner join DictSchemeName ds
on s.schemeName = ds.id
inner join DictTableName dt
on s.tableName = dt.id;
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甚至更进一步:
select ds.schemeName,
dt.tableName
from ServiceSublayer ss
inner join Service s
on ss.serviceId = s.id
inner join DictSchemeName ds
on ss.schemeName = ds.id
inner join DictTableName dt
on ss.tableName = dt.id
where ss.sId = 3
and s.applicationId = 'prga';
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