Scipy:稀疏矩阵是否支持高级索引?

Noo*_*bot 8 python numpy scipy

没问题:

>>> t = np.array([[1,1,1,1,1],[2,2,2,2,2],[3,3,3,3,3],[4,4,4,4,4],[5,5,5,5,5]])
>>> x = np.arange(5).reshape((-1,1)); y = np.arange(5)
>>> print (t[[x]],t[[y]])
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大问题:

>>> s = scipy.sparse.csr_matrix(t)
>>> print (s[[x]].toarray(),s[[y]].toarray())
Traceback (most recent call last):
  File "<pyshell#22>", line 1, in <module>
:               :
:               :
ValueError: data, indices, and indptr should be rank 1
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s.toarray()[[x]]效果很好,但由于我的数组太大,使用稀疏矩阵打败了我的整个目的.我已经检查了与某些稀疏矩阵相关的属性和方法,以获取引用高级索引的任何内容,但没有骰子.有任何想法吗?

Jai*_*ime 14

稀疏矩阵具有非常有限的索引支持,可用的内容取决于矩阵的格式.

例如:

>>> a = scipy.sparse.rand(100,100,format='coo')
>>> a[2:5, 6:8]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'coo_matrix' object has no attribute '__getitem__'
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但

>>> a = scipy.sparse.rand(100,100,format='csc')
>>> a[2:5, 6:8]
<3x2 sparse matrix of type '<type 'numpy.float64'>'
    with 0 stored elements in Compressed Sparse Column format>
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虽然

>>> a[2:5:2, 6:8:3]
Traceback (most recent call last):
...
ValueError: slicing with step != 1 not supported
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还有

>>> a = scipy.sparse.rand(100,100,format='dok')
>>> a[2:5:2, 6:8:3]
Traceback (most recent call last):
...
NotImplementedError: fancy indexing supported over one axis only
>>> a[2:5:2,1]
<3x1 sparse matrix of type '<type 'numpy.float64'>'
    with 0 stored elements in Dictionary Of Keys format>
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乃至

>>> a = scipy.sparse.rand(100,100,format='lil')
>>> a[2:5:2,1]
<2x1 sparse matrix of type '<type 'numpy.int32'>'
    with 0 stored elements in LInked List format>
C:\Python27\lib\site-packages\scipy\sparse\lil.py:230: SparseEfficiencyWarning: Indexing into a lil_matrix with multiple indices is slow. Pre-converting to CSC or CSR beforehand is more efficient.
  SparseEfficiencyWarning)
>>> a[2:5:2, 6:8:3]
<2x1 sparse matrix of type '<type 'numpy.int32'>'
    with 0 stored elements in LInked List format>
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  • @NoobSaibot 是的,我认为上面总结了稀疏矩阵的索引可能性。我几乎可以肯定,使用 2D 数组进行索引对任何格式都不起作用,尽管我相信 LIL 将采用两个 1D 数组作为索引,并返回一个行向量。 (2认同)