“set -eu”在 bash 脚本中起什么作用?

Kan*_*bot 4 bash

我用谷歌搜索并找不到这种组合的解释。

set -eubash shell 脚本的开始部分做了什么?

(我可以找到一些解释,-e但没有-eu。)

pop*_*pey 9

bash 手册页的shell 内置命令部分下,对该set命令进行了解释。-e-u可以单独设置,但在调试时经常与-xtoset -eux或 shebang to组合使用#!/bin/bash -eux

-e      Exit  immediately  if  a  pipeline  (which  may  consist of a single simple
        command), a list, or a compound command (see SHELL  GRAMMAR  above),  exits
        with  a non-zero status.  The shell does not exit if the command that fails
        is part of the command list immediately following a while or until keyword,
        part  of  the  test  following  the  if or elif reserved words, part of any
        command executed in a && or || list except the command following the  final
        &&  or  ||,  any  command  in  a pipeline but the last, or if the command's
        return value is being inverted with !.  If a compound command other than  a
        subshell  returns  a  non-zero status because a command failed while -e was
        being ignored, the shell does not exit.  A trap on ERR, if set, is executed
        before  the  shell exits.  This option applies to the shell environment and
        each subshell environment separately  (see  COMMAND  EXECUTION  ENVIRONMENT
        above),  and  may cause subshells to exit before executing all the commands
        in the subshell.

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-u      Treat  unset variables and parameters other than the special parameters "@"
        and "*" as an error when performing parameter expansion.  If  expansion  is
        attempted  on  an  unset  variable  or parameter, the shell prints an error
        message, and, if not interactive, exits with a non-zero status.
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  • 为了添加出色的答案,您会在脚本中看到这一点以改进错误处理。如果没有“-e”,当底层命令返回错误代码时,脚本将继续执行。在许多情况下,您希望在此时终止脚本。`-u` 防止意外使用未定义的变量,例如,如果脚本使用变量 `$foo`,但之前未设置其值,则 `-u` 标志将告诉 bash 停止执行时出现错误。 (3认同)