sed -e 's/72;/72, next_val = 0x11111111;/;/@/{h;s/test/next/g;x;G}'
fmt_vuln.c > fmt_vuln2.c
Run Code Online (Sandbox Code Playgroud)
你能告诉我是什么意思;/@/{h;s/test/next/g;x;G}吗?
/@/ # For pattern-space containing the character @ do the following
{
h # place a copy of the pattern-space into the hold-space
s/test/next/g # replace all instances of "test" with "next" in the pattern-space
x # swap the pattern-space with the hold-space
G # append a newline followed by contents of hold-space to the pattern-space
}
Run Code Online (Sandbox Code Playgroud)
因此,对于包含 @ 的每一行,将打印模式空间的修改版本,然后是原始版本(保留空间包含未修改的版本)。
请参阅Sed 的命令摘要
;/@/{h;s/test/next/g;x;G}?
/@/ search for an `@` sign
{} for the lines where that is true do this 'block' of code
h put the pattern match in the hold space
s/ substitute test for next everywhere in the space
g do the previous substitution for all matches on the line
x swap the hold with the pattern space
G Add a new line with the contents of the hold space.
Run Code Online (Sandbox Code Playgroud)