如果匹配，则提取多行

Question

我有一个命令可以输出有关块中所有 DIMM 插槽的信息，如下所示：

ID    SIZE TYPE
44    105  SMB_TYPE_MEMDEVICE (type 17) (memory device)

  Manufacturer: NO DIMM
  Serial Number: NO DIMM
  Asset Tag: NO DIMM
  Location Tag: P1-DIMMD1
  Part Number: NO DIMM

  Physical Memory Array: 43
  Memory Error Data: Not Supported
  Total Width: 0 bits
  Data Width: 0 bits
  Size: Not Populated
  Form Factor: 9 (DIMM)
  Set: None
  Rank: Unknown
  Memory Type: 2 (unknown)
  Flags: 0x4
        SMB_MDF_UNKNOWN (unknown)
  Speed: Unknown
  Configured Speed: Unknown
  Device Locator: P1-DIMMD1
  Bank Locator: P0_Node1_Channel0_Dimm0
  Minimum Voltage: 1.20V
  Maximum Voltage: 1.20V
  Configured Voltage: 1.20V

这些块以ID SIZE TYPE标题开始，以配置的电压信息结束。该命令为每个 DIMM 输出这些数据块之一，每个 DIMM 由一个空行分隔。

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我希望能够根据Location Tag字段获取特定 DIMM 插槽的信息块，但我不确定如何去做。我很确定这可以完成，awk但只知道如何在匹配awk '/P1-DIMMD1/'之前打印匹配或行awk '/P1-DIMMD1/ {print a}{a=$0}'

有谁知道如果Location Tag与我的搜索 ( P1-DIMMD1)匹配，我如何提取整个数据块？

Answer 1

以下将匹配标签变量中给出的标签：

awk -v tag=P1-DIMMD1 '/ID    SIZE TYPE/ { block = $0; output = 0; next } { block = block "\n" $0 } /Location Tag/ { output = ($0 ~ tag) } /Configured Voltage/ && output { print block }'

AWK 脚本是

/ID    SIZE TYPE/ {
  block = $0
  output = 0
  next
}

{ block = block "\n" $0 }

/Location Tag/ { output = ($0 ~ tag) }

/Configured Voltage/ && output { print block }

我们在block变量中累积一个块，如果我们在过程中看到正确的标签，则在到达块的末尾时输出它。