小编ima*_*asy的帖子

如何替换熊猫中的值?

尝试将“KDDTest+.csv”的倒数第二列中的 23 个不同标签 分为四组。请注意,在执行此操作之前,我已删除了 csv 的最后一列。

我已经阅读了 .csv 文件使用

df = pd.read_csv('KDDTrain+.csv', header=None, names = col_names)
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在哪里

col_names = ["duration","protocol_type","service","flag","src_bytes",
    "dst_bytes","land","wrong_fragment","urgent","hot","num_failed_logins",
    "logged_in","num_compromised","root_shell","su_attempted","num_root",
    "num_file_creations","num_shells","num_access_files","num_outbound_cmds",
    "is_host_login","is_guest_login","count","srv_count","serror_rate",
    "srv_serror_rate","rerror_rate","srv_rerror_rate","same_srv_rate",
    "diff_srv_rate","srv_diff_host_rate","dst_host_count","dst_host_srv_count",
    "dst_host_same_srv_rate","dst_host_diff_srv_rate","dst_host_same_src_port_rate",
    "dst_host_srv_diff_host_rate","dst_host_serror_rate","dst_host_srv_serror_rate",
    "dst_host_rerror_rate","dst_host_srv_rerror_rate","label"]
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如果我打印出数据框的前 5 行,这是输出(请注意“标签”列):

使用 print(df.head(5))

   duration protocol_type  ... dst_host_srv_rerror_rate    label
0         0           tcp  ...                     0.00   normal
1         0           udp  ...                     0.00   normal
2         0           tcp  ...                     0.00  neptune
3         0           tcp  ...                     0.01   normal
4         0           tcp  ...                     0.00   normal
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我已经根据我在网上找到的内容尝试了这两种分组方法:

方法一:

df.replace(to_replace = ['ipsweep.', 'portsweep.', 'nmap.', 'satan.'], value …
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python dataframe pandas

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