小编Shi*_*bir的帖子

可能重复:
mysql_fetch_array()期望参数1是资源,在select中给出boolean

以下是我的简单搜索查询,但它显示

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in 
C:\xampp\htdocs\project\p\answer.php on line 52
No Result Found 

52行:

$numserach = mysql_num_rows($search_sql);

PHP代码:

$search_sql = mysql_query("SELECT * FROM questions WHERE q_name LIKE %$search%");
            $numserach = mysql_num_rows($search_sql);

            if($numserach == 1)
            {
                echo $numserach. "Result found";
            }
            else
            {
                echo "No Result Found";
            }

谢谢:)