requests使用库发出请求时https://stackoverflow.com
page = requests.get(url='https://stackoverflow.com')
print(page.content)
我得到以下信息：
<!DOCTYPE html>
<html class="html__responsive html__unpinned-leftnav">
<head>
<title>Stack Overflow - Where Developers Learn, Share, & Build Careers</title>
<link rel="shortcut icon" href="https://cdn.sstatic.net/Sites/stackoverflow/Img/favicon.ico?v=ec617d715196">
<link rel="apple-touch-icon" href="https://cdn.sstatic.net/Sites/stackoverflow/Img/apple-touch-icon.png?v=c78bd457575a">
<link rel="image_src" href="https://cdn.sstatic.net/Sites/stackoverflow/Img/apple-touch-icon.png?v=c78bd457575a">
..........
这里的这些源代码具有绝对路径，但是当使用requests-htmljs 渲染运行相同的 URL 时
with HTMLSession() as session:
page = session.get('https://stackoverflow.com')
page.html.render()
print(page.content)
我得到以下信息：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>StackOverflow.org</title>
<script type="text/javascript" src="lib/jquery.js"></script>
<script type="text/javascript" src="lib/interface.js"></script>
<script type="text/javascript" src="lib/window.js"></script>
<link href="lib/dock.css" rel="stylesheet" …对于这个 Pythonfor循环：
for i in range(n-2,-1,-1):
C++ 中的等效代码语法是什么？