小编Mar*_*ura的帖子

ScalaMock 3.使用函数参数模拟方法

我想用函数参数和函数参数模拟方法,结合curried参数,如:

trait Secured {

  def IsAuthenticated(f: AuthenticatedData => Request[AnyContent] => Result) = {
    // auth code
    f(AuthenticatedData.create(request))(request)
  }

  def IsOwnerOfTestrun(id: String)(f: Testrun => AuthenticatedData => 
        Request[AnyContent] => Result) = 
    IsAuthenticated { authenticatedData => implicit request => {
      // auth code
      f(testrun)(authenticatedData)(request)
  }
}
Run Code Online (Sandbox Code Playgroud)

我如何在安全特征中模拟这些方法?

我使用Play 2.1.1/Scala 2.10.0与ScalaMock 3.0.1与Specs2:

"org.scalamock" %% "scalamock-specs2-support" % "3.0.1" % "test"
Run Code Online (Sandbox Code Playgroud)

scala mocking scala-2.10 playframework-2.1

6
推荐指数
0
解决办法
413
查看次数

使用iOS乐器启动应用程序是不可靠的

我使用以下命令在应用程序(不是模拟器)上启动我的iOS应用程序(已经安装了应用程序).

instruments \
          -w c717fa22472d7b691ae5763af90e1e44244ad85a \
          -t /Applications/Xcode.app/Contents/Applications/Instruments.app/Contents/PlugIns/AutomationInstrument.bundle/Contents/Resources/Automation.tracetemplate \
          -D "/Users/mj/Desktop/apps/trace" \
          LPSimpleExample-cal \
          -e UIARESULTSPATH /Users/mj/Desktop/apps \
          -e UIASCRIPT /Users/mj/Desktop/apps/_run_loop.js
Run Code Online (Sandbox Code Playgroud)

它正在工作的10次中有6次.如果出现错误,我会收到以下消息:

2013-10-07 16:45:51.553 instruments[9891:1207] unable to locate CFBundleIdentifier for path: LPSimpleExample-cal
2013-10-07 16:45:51.555 instruments[9891:1207] Recording cancelled : At least one target    failed to launch; aborting run
Instruments Trace Error : Error Domain=com.apple.instruments Code=1 "Error Starting   Recording" UserInfo=0x7faccbef8fa0 {NSLocalizedDescription=Error Starting Recording,   NSLocalizedRecoverySuggestion=At least one target failed to launch; aborting run}
Instruments Trace Error : Failed to start trace.
Run Code Online (Sandbox Code Playgroud)


对我来说,看起来仪器有一个错误.我试图在不同的情况下启动应用程序超过100次,我无法分析错误模式.设备崩溃日志说:

Process: …
Run Code Online (Sandbox Code Playgroud)

macos instruments ios xcode-instruments ios7

5
推荐指数
1
解决办法
1854
查看次数

播放2.1 Json序列化的特征

Play 2.1(Json.format [...])中的实验性"初始化"功能仅适用于案例类(请参阅此处).如何为特征编写隐式的自定义格式.我有以下构造:

sealed trait Plan {
  def id: String
  def name: String
  def apps: Int
  def users: Int
  def testruns: Int
  def price: Int
  def prio: Int
}
Run Code Online (Sandbox Code Playgroud)

以下是扩展特质计划的案例类.

case class Start(
                  id: String = "start",
                  name: String = "Start",
                  apps: Int = 1,
                  users: Int = 1,
                  testruns: Int = 10,
                  price: Int = 99,
                  prio: Int = 30) extends Plan

case class Pro(
                id: String = "pro",
                name: String = "Pro",
                apps: Int = 2, …
Run Code Online (Sandbox Code Playgroud)

json scala playframework-2.0

2
推荐指数
1
解决办法
1855
查看次数