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带/不带指针的函数原型用法的区别

我正在学习简单的 C++ 教程。

#include <iostream>
using namespace std;

int main()
{
  int a = 1, b = 2;

  cout << "Before swapping " << endl;
  cout << "a = " << a << endl;
  cout << "b = " << b << endl;

  swap(a,b);

  cout << endl;
  cout << "After swapping " << endl;
  cout << "a = " << a << endl;
  cout << "b = " << b << endl;

  return 0;
}

void swap(int &n1, int &n2) …
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c++ pointers reference

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