有没有办法将返回的行数限制为游标?我有一个有大约4000个联系人的电话,我只需要其中一些.
这是我正在使用的代码
db = new dBHelper(this);
ContentResolver cr = getContentResolver();
Cursor cursor;
cursor = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null, null, ContactName + " ASC");
Log.i(TAG, CLASSNAME + " got contacts entries");
for (int it = 0; it <100 ; it++){//cursor.getCount()
Log.i(TAG, CLASSNAME + " getting string");
String mytimes_contacted = cursor.getString(cursor.getColumnIndex(dBHelper.times_contacted));
Log.i(TAG, CLASSNAME + " done from the string");
}
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我得到的日志是
I/Check(11506): [ContactsPicker] got contacts entries
I/Check(11506): [ContactsPicker] getting first string
D/AndroidRuntime(11506): Shutting down VM
W/dalvikvm(11506): threadid=1: thread exiting with uncaught exception (group=0x2aac8578)
D/dalvikvm(11541): …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用C++将十六进制数转换为一个短(2字节)一切都没问题,除了一件事......签名从短转换为字节(最后一次测试)
我发现了这个问题,并没有真正从中受益:可移植的有符号/无符号字节转换,C++
这是我的测试:
// test 1 - positive B2Short (success)
byte *b = new byte[2];
b[0] = 0x10; //low byte
b[1] = 0x00; //heigh byte
signed short test = 0;
test = ByteToShort(b);
cout << test << endl;
// test 2 - negative B2Short (success)
b[0] = 0xF0; //low byte
b[1] = 0xFF; //heigh byte
test = 0;
test = ByteToShort(b);
cout << test << endl;
// test 3 - positive Short2B (success)
signed short n = 11;
ShortToByte(n, …Run Code Online (Sandbox Code Playgroud)