我不理解Guava的集合的行为#isremp()方法的区别:
public static <E> SetView<E> difference(final Set<E> set1, final Set<?> set2) {
checkNotNull(set1, "set1");
checkNotNull(set2, "set2");
final Predicate<Object> notInSet2 = Predicates.not(Predicates.in(set2));
return new SetView<E>() {
@Override public Iterator<E> iterator() {
return Iterators.filter(set1.iterator(), notInSet2);
}
@Override public int size() {
return Iterators.size(iterator());
}
@Override public boolean isEmpty() {
return set2.containsAll(set1);
}
@Override public boolean contains(Object element) {
return set1.contains(element) && !set2.contains(element);
}
};
}
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更确切地说,我不明白如何set2.containsAll(set1);使用它的结果isEmpty().
举个例子:
差异(C,D,E)肯定不会是空的.但Sets.difference(set1,set2).isEmpty()将返回true,因为(A,B,C,D,E).containsAll(A,B)为真.
即使javadoc说,我也不明白逻辑:
{@code set2}也可能包含{@code set1}中不存在的元素; …