小编gSa*_*enz的帖子

我在这里有这个代码,你可以从我的伪代码中看到我正在努力实现的目标

select *

from dbo.BenefitsForms
     inner join Dependents on BenefitsForms.UserId = Dependents.BenefitsForm_UserId
     inner join CoverageLevels on BenefitsForms.MedicalId = CoverageLevels.Id

where (BenefitsForms.MedicalId > 0 AND BenefitsForms.MedicalId < 13)
  AND Dependents.IsSpouse = CASE when CoverageLevels.[Level] = 2 then 1
                                 when CoverageLevels.[Level] = 3 then 0 end
                                 when CoverageLevels.[Level] = 4 then [any, it doesnt matter] <--- my desire but it doesn't work.

我怎样才能在括号中获得我想要的效果？如果Coverage Level = 4那么我不关心Dependents.IsSpouse是什么,我甚至不需要再按它排序了.

我试图隐藏非主页的页脚.以下是我的尝试,这是网站

.home #first  {
    width:950px;
    margin-top:20px ;
    border-top: 1px dotted #9bacd4;
    background:#ff0000;
}


.home #first img {
    margin:5px;
}

.home #first h3
{
   font-size:16px;
   font-weight:bold;
   margin:5px 0px 15px 15px;    
}

#first {
    display:none;
}

我在比较Mysql数据库中的两个值并显示最低值时遇到问题.

比如我有这个:

value1 = 23.4
value2 = 4.479

我试过这个:

ORDER BY CAST(column AS SIGNED) ASC

但它不起作用

同样,字段类型是VARCHAR.

我要找的结果应该是23.4而不是4.479

有什么建议？

假设如下

col1      col2       col3       col4
------+----------+---------+---------
abc   |          |         |            

是的,col1-4中有空格!

我想选择不是空格的列. On row 1 it's col1, but on row 20 it may be col3, row 55 it may be col2, and so on. I need to return just that column.

There will always be only one column with a stored value within this range of four columns, I just need the one that actually has information in it.

This will be part of a greater query for …