我试图从一个段落中提取句子,模式就像
Current. time is six thirty at Scotland. Past. time was five thirty at India; Current. time is five thirty at Scotland. Past. time was five thirty at Scotland. Current. time is five ten at Scotland.
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当我使用正则表达式时
/current\..*scotland\./i
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这匹配所有字符串
Current. time is six thirty at Scotland. Past. time was six thirty at India; Current. time is five thirty at Scotland. Past. time was five thirty at Scotland. Current. time is five ten at Scotland.
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相反,我想在第一次出现"."时停止.对所有捕获组如
Current. time is six thirty …Run Code Online (Sandbox Code Playgroud) 在我的控制器中,我有以下4种方法,但这些方法具有代码相似性
before_filter :load_person, except: [:autocomplete]
before_filter :validate_twitter, only: [:recent_tweets, :commonly_following]
before_filter :validate_linkedin, only: [:common_connections]
before_filter :validate_facebook, only: [:mutual_friends]
before_filter :validate_google, only: [:meetings]
def validate_linkedin
@linkedin_account = current_user.social_account("LinkedIn")
return render json: { message: "You are not connected to your LinkedIn account" } if @linkedin_account.blank?
return render json: { message: "No Linkedin url for #{@person.name}" } if @person.linkedin_url.blank?
end
def validate_twitter
@twitter_account = current_user.social_account("Twitter")
return render json: { message: "You are not connected to your Twitter account" } if @twitter_account.blank?
return render …Run Code Online (Sandbox Code Playgroud) 我想转换这个数组
[['a', 'b'],['c', 'd'],['e', 'f']]
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这个哈希
{
"a" : "c",
"b" : "d"
},
{
"a" : "e",
"b" : "f"
}
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怎么做?
我试图使用group_by和正常的迭代器,但到目前为止没有运气.有任何想法吗?
如何在rails 4中实现以下功能?
这是我的 PostgreSQL 查询并且正常工作
SELECT lower(name) as c_name, count(*) as cc FROM categories GROUP BY c_name ORDER BY cc desc LIMIT 3
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ii给我以下结果
"ecommerce solutions";6
"vmware";6
"big data analytics";5
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但是当我在 Rails 4 中编写相同的查询时
Category.select("lower(name) as c_name, count(*) as cc").group("c_name").order("cc desc").limit(3)
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以上查询生成以下查询,与上面的 PostgreSQL 查询相同
SELECT lower(name) as c_name, count(*) as cc FROM "categories" GROUP BY c_name ORDER BY cc desc LIMIT 3
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给出以下结果
[#<Category id: nil>, #<Category id: nil>, #<Category id: nil>]
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为什么会这样?当我将查询切到
Category.select("lower(name)").limit(3)
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这也不起作用,结果变成
[#<Category id: nil>, #<Category id: …Run Code Online (Sandbox Code Playgroud) 我有带有Apartment gem的多租户 Rails 应用程序,我可以使用Apartment-sidekiq成功切换每个工作人员中的数据库租户。但 sidekiq 工作人员为所有租户使用相同的 redis 服务器。我也想在redis上有完全的隔离。有没有一种方法可以让我为每个租户使用单独的 redis 主机,而不会影响使用 sidekiq middeware 进行的大量代码更改。
租户配置示例
TENANT_POOL = {
tenant_1: ConnectionPool.new { Redis.new(url: ENV['REDIS_URL1']) },
tenant_2: ConnectionPool.new { Redis.new(url: ENV['REDIS_URL2']) }
}
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例如。工人
class SendMailWorker
include Sidekiq::Worker
def perform(args)
puts "In Worker Tenant: #{Apartment::Tenant.current}, #{Sidekiq.redis_pool.inspect}"
end
end
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客户端中间件
class MyMiddleware::Client::ChangeRedisPool
def call(worker_class, job, queue, redis_pool)
#Can I change redis pool/client here to execute job in separate redis
yield
end
end
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服务器中间件
class MyMiddleware::Server::ChangeServerRedisPool
def call(worker, job, queue)
#Can I …Run Code Online (Sandbox Code Playgroud)