小编J X*_*kcd的帖子

当我conda init cmd.exe在正常或管理模式下运行时，出现以下错误。

WARNING: Cannot install xonsh wrapper without a python interpreter in prefix: C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\Scripts\conda.exe
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\Scripts\conda-env.exe
modified      C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\Scripts\conda-script.py
modified      C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\Scripts\conda-env-script.py
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\condabin\conda.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\Library\bin\conda.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\condabin\_conda_activate.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\condabin\rename_tmp.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\condabin\conda_auto_activate.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\condabin\conda_hook.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\Scripts\activate.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\condabin\activate.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\condabin\deactivate.bat
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\Scripts\activate
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\Scripts\deactivate
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\etc\profile.d\conda.sh
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\etc\fish\conf.d\conda.fish
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\shell\condabin\Conda.psm1
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\shell\condabin\conda-hook.ps1
needs sudo    C:\Users\JASONL~1\AppData\Local\Temp\_MEI202282\etc\profile.d\conda.csh
modified      HKEY_CURRENT_USER\Software\Microsoft\Command Processor\AutoRun

这是什么意思以及如何解决它？我应该尝试全新安装吗？

我将如何使用向量函数，其中向量名称是一个变量？我所指的粗略草图：

void someFunc(int x) {
    vector<int>v0;
    vector<int>v1;
    vector<int>v2;
    switch (x) {
    case 0: //var will be assigned v0
    case 1: //var will be assigned v1
    case 2: //var will be assigned v2
    }
    var.assign(10, 1); //eg. when x == 1, it will be v1.assign(10,1)
}

假设我有一个返回的调用函数，我可以让它返回到返回地址之前的 x 行吗？例如。

call foo --> line 72 - calling bar will return here.
mov ax,1
call bar --> line 74

bar:
mov ax,2
ret (-2)

我的目标是创建一个可调用的函数，该函数将始终返回到调用地址之前的 2 行，而不必使用十亿个标志和标签。