小编veo*_*ote的帖子

我正在使用JPA 2.1.2.

我想用where子句执行select查询.where语句应该比较(不等于)存储在数据库(字符串)中的枚举.

@Entity
@Table(name = "MY_ENTITY")
public class MyEntity implements Serializable {

    @Column(name = "REMINDER_STATE")
    @Enumerated(EnumType.STRING)
    private ReminderStage reminderStage;

    ...
}

class DaoImpl{
 ....

    @Override
    public List<MyEntity> findAll(ReminderStage stage) {
        return em.createQuery("SELECT c FROM MyEntity c  WHERE  c.reminderStage != :reminderStage", MyEntity.class)
                .setParameter("reminderStage", stage).getResultList();

    }
}

但是当我执行查询时,我得到以下异常:

...
[28.07.14 08:27:07:910 CEST] 0000004e SystemErr     R Caused by: <openjpa-2.1.2-SNAPSHOT-r422266:1530146 nonfatal user error> org.apache.openjpa.persistence.ArgumentException: An error occurred while parsing the query filter 'SELECT c FROM CertInfo c  WHERE  c.reminderStage != :reminderStage'. Error message: …

我正在使用Primefaces 5.0来创建动态数据表.

我的DataObject有一些必需的字段和一个可选的"tupel"列表(键值对).可选列表的大小可能不同.因此,我需要一个动态机制来显示Primefaces.DataTable中的DataObject列表.

我的方法如下:

public class DataObject {
    private String staticval1;
    private String staticval2;

    private List<Tupel> optionalValues;


    // .. getter, setter, hashCode, toString.....
}

public class Tupel{
    private String id;
    private String value;
}

@ManagedBean
@ViewScoped
public class TableOverviewBean {
    private List<DataObject> data;

    @EJB
    private IMyDao myDao;

    @PostConstruct
    public void init() {
        data = myDao.findAll();
    }

    public List<DataObject> getData() {
        return data;
    }

    public void setData(List<DataObject> data) {
        this.data = data;
    }
}

    <h:form>
        <p:dataTable value="#{tableOverviewBean.data}" var="data">
            <p:column headerText="static1">
                <h:outputText …

今天我想尝试新的PrimeFaces版本3.4.RC1.对于图表,有一个名为datatipFormat的新属性.

我想只在折线图中显示值(y轴)作为datatip.像这样:

<p:lineChart value="#{...}" datatipFormat="y-value"/>

我该怎么做只显示这个？我找不到一个带有模板String的例子.

最好的问候Veote

我正在使用PrimeFaces 4.0的JSF 2.

我有一个带有一些输入和验证的表单.从对话框中选择实体时,某些字段可能会自动填充.在我提交整个表单(并验证)之前选择实体时,这很好用.但是当我在验证后选择实体时,组件的更新不起作用.

JSF页面:

<h:form id="form">
    <p:inputText id="id" value="#{bean.user.id}" required="true" 
        onclick="PF('usersDialog').show()" />
    <p:inputText id="name" value="#{bean.user.name}" required="true"
        onclick="PF('usersDialog').show()" />
    <p:commandButton value="submit" action="#{bean.submit}" update=":form" />
</h:form>

<p:dialog widgetVar="usersDialog">
    <h:form>
        <p:dataTable value="#{bean.users}" var="user">
            <p:column>
                <p:commandButton value="choose" onclick="PF('usersDialog').hide()"
                    process="@this" action="#{bean.select(user)}" update=":form" />
            </p:column>
            <p:column>
                <h:outputText value="#{user.name}" />
            </p:column>
        </p:dataTable>
    </h:form>
</p:dialog>

我知道它的JSF生命周期,但我无法解决它.那么在从对话框中选择新实体时,如何在验证失败后更新表单？

提前致谢.

我需要一个hashCodeJava实现,它忽略了我的类中字段的顺序Edge.Node首先可能是Node第二个,第二个可能是Node第一个.

这是我的方法取决于顺序:

public class Edge {
    private Node first, second;

    @Override
    public int hashCode() {
        int hash = 17;
        int hashMultiplikator = 79;
        hash = hashMultiplikator * hash
                + first.hashCode();
        hash = hashMultiplikator * hash
                + second.hashCode();
        return hash;
    }
}

有没有办法计算一个哈希值,这个哈希值对于以下边缘是相同但唯一的？

Node n1 = new Node("a");
Node n2 = new Node("b");
Edge ab = new Edge(n1,n2);
Edge ba = new Edge(n2,n1);

ab.hashCode() == ba.hashCode()应该是true.

I want to call a local Stateless-EJB from on ejb project from another singleton-EJB in another ejb-project. Both EJB-Projects are in the same ear file. The Application Server is a WebSphere Application Server 8.0.0.1.

First EJB 3.1-Project (PersistenceEJB.jar):

Interface

@Local
public interface TaskInfoDao extends DaoTemplate<TaskInfo> {
    public int deleteAll();
}

The Stateless Bean:

@Stateless
@TransactionAttribute(TransactionAttributeType.REQUIRED)
public class TaskInfoDaoImpl implements TaskInfoDao {
    private static final long serialVersionUID = 1L;

    @PersistenceContext(unitName = "MyDatasource")
    private EntityManager em;

    @Override
    public int deleteAll() {
        Query …

我正在尝试在部署在 IBM WebSphere Application Server 8.0.0.8 上的 JSF 应用程序中使用一些错误页面。它们在 中声明如下web.xml：

<error-page>
    <error-code>403</error-code>
    <location>/error403.jsp</location>
</error-page>
<error-page>
    <exception-type>javax.faces.application.ViewExpiredException</exception-type>
    <location>/expired.xhtml</location>
</error-page>
<error-page>
    <error-code>500</error-code>
    <location>/error500.xhtml</location>
</error-page>

但是，它们似乎不起作用。例如，当我ViewExpiredException在重新启动应用程序后得到 a 时，我没有重定向到错误页面，但我SRVE0260E在服务器日志中收到以下错误：

Error Page Exception
SRVE0260E: The server cannot use the error page specified for your application to handle the Original Exception printed below.

Original Exception:
Error Message: javax.servlet.ServletException: /help.xhtmlNo saved view state could be found for the view identifier: /help.xhtml
Error Code: 500
Target Servlet: Faces Servlet
Error Stack:
javax.faces.application.ViewExpiredException: …

我在带有MySQL 5.0 DB的WebSphere Application Server 8上使用OpenJPA 2.2.0.

我有一个对象列表,我想合并到数据库中.

就像是:

for (Object ob : list) {
            Long start = Calendar.getInstance().getTimeInMillis();
            em = factory.createEntityManager();
            em.getTransaction().begin();

            em.merge(ob);

            em.getTransaction().commit();
            em.close();
            Long end = Calendar.getInstance().getTimeInMillis();
            Long diff = end - start;
            LOGGER.info("Time: " + diff);
        }

当我运行这个循环时,我需要大约300-600毫秒来合并一个对象.当我删除行"em.merge(ob);"时 然后我需要"0"毫秒来迭代1个列表对象.

所以我的问题是:我可以做些什么来缩短合并一个对象的时间？

谢谢!

我想离开加入2桌.所以左表的所有属性都应该显示在结果表中,无论它是否可以与其他表连接.

当我这样做时,我没有得到预期的结果

week_table:
 date       kw note
 ---------- -- ----
 2012-04-01  0 NULL
 2012-04-02  0 NULL

fact_table:
id number_of_application number_of_cluster number_of_jvm number_of_node number_of_was fk_wasversion fk_date    fk_domain fk_osname fk_osarch fk_osversion fk_stage
 -- --------------------- ----------------- ------------- -------------- ------------- ------------- ---------- --------- --------- --------- ------------ --------
  1                   114                 8            80             18            18 6.0           2012-04-01 domain1   Linux     sparc     2            stage1
  2                   114                 8            80             18            18 6.0           2012-04-02 domain1   Linux     sparc     2            stage1
  3                   114                 8            80             18            18 6.0           2012-04-01 domain1   AIX       sparc     2 …

我需要在Apache Openjpa 2的select子句中执行子查询.JPA是否支持SELECT子句中的子查询？

我的查询是这样的:

SELECT t.date, t.value, 
  (SELECT COUNT(DISTINCT t2.value2) FROM table t2 WHERE t2.date = t.date)
FROM table t
WHERE ...

当我执行我的查询时,我得到一个类强制转换异常:

Exception in thread "main" <openjpa-2.1.1-SNAPSHOT-r422266:1141200 nonfatal user error> org.apache.openjpa.persistence.ArgumentException: 
    at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:872)
    at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:794)
    at org.apache.openjpa.kernel.DelegatingQuery.execute(DelegatingQuery.java:542)
    at org.apache.openjpa.persistence.QueryImpl.execute(QueryImpl.java:315)
    at org.apache.openjpa.persistence.QueryImpl.getResultList(QueryImpl.java:331)
Caused by: java.lang.ClassCastException: org.apache.openjpa.jdbc.sql.LogicalUnion$UnionSelect incompatible with org.apache.openjpa.jdbc.sql.SelectImpl
    at org.apache.openjpa.jdbc.sql.SelectImpl.setParent(SelectImpl.java:579)
    at org.apache.openjpa.jdbc.kernel.exps.SelectConstructor.newSelect(SelectConstructor.java:147)
    at org.apache.openjpa.jdbc.kernel.exps.SelectConstructor.evaluate(SelectConstructor.java:87)
    at org.apache.openjpa.jdbc.kernel.exps.SubQ.appendTo(SubQ.java:209)
    at org.apache.openjpa.jdbc.kernel.exps.SubQ.appendTo(SubQ.java:203)
    at org.apache.openjpa.jdbc.kernel.exps.SubQ.newSQLBuffer(SubQ.java:167)
    at org.apache.openjpa.jdbc.kernel.exps.SubQ.selectColumns(SubQ.java:153)
    at org.apache.openjpa.jdbc.kernel.exps.SubQ.select(SubQ.java:148)
    at org.apache.openjpa.jdbc.kernel.exps.SelectConstructor.select(SelectConstructor.java:372)
    at org.apache.openjpa.jdbc.kernel.JDBCStoreQuery.populateSelect(JDBCStoreQuery.java:295)
    at org.apache.openjpa.jdbc.kernel.JDBCStoreQuery.access$100(JDBCStoreQuery.java:86)
    at org.apache.openjpa.jdbc.kernel.JDBCStoreQuery$1.select(JDBCStoreQuery.java:267)
    at org.apache.openjpa.jdbc.sql.LogicalUnion.select(LogicalUnion.java:297)
    at org.apache.openjpa.jdbc.kernel.JDBCStoreQuery.populateUnion(JDBCStoreQuery.java:265)
    at org.apache.openjpa.jdbc.kernel.JDBCStoreQuery.executeQuery(JDBCStoreQuery.java:211)
    at …

我在Eclipse Juno中使用WebSphere Application Server V8.5 Liberty Profile.我配置了我的AppServer(server.xml)并添加了jsp-2.2,jsf2.0,localConnector-1.0和servlet-3.0功能.

当我部署我的项目并在浏览器中打开JSP-Page时,一切都很顺利.但是当我想打开一个JSF-Page时,我得到以下异常:

[ERROR   ] An error occured while initializing MyFaces: org.apache.myfaces.spi.impl.DefaultFacesConfigurationMergerFactory cannot be cast to org.apache.myfaces.spi.FacesConfigurationMergerFactory
[ERROR   ] Uncaught.init.exception.thrown.by.servlet
[ERROR   ] SRVE0266E: Error occured while initializing servlets: javax.servlet.ServletException: SRVE0207E: Uncaught initialization exception created by servlet
    at com.ibm.ws.webcontainer.servlet.ServletWrapper.init(ServletWrapper.java:382)
    at com.ibm.ws.webcontainer.osgi.servlet.ServletWrapper.init(ServletWrapper.java:83)
    at com.ibm.ws.webcontainer.servlet.ServletWrapper.loadOnStartupCheck(ServletWrapper.java:1353)
    at com.ibm.ws.webcontainer.webapp.WebApp.doLoadOnStartupActions(WebApp.java:862)
    at com.ibm.ws.webcontainer.webapp.WebApp.commonInitializationFinally(WebApp.java:831)
    at com.ibm.ws.webcontainer.webapp.WebApp.initialize(WebApp.java:753)
    at com.ibm.ws.webcontainer.webapp.WebApp.initialize(WebApp.java:5694)
    at com.ibm.ws.webcontainer.osgi.DynamicVirtualHost.createRunnableHandler(DynamicVirtualHost.java:220)
    at com.ibm.ws.http.internal.VirtualHostImpl.discriminate(VirtualHostImpl.java:165)
    at com.ibm.ws.http.dispatcher.internal.channel.HttpDispatcherLink.ready(HttpDispatcherLink.java:157)
    at com.ibm.ws.http.channel.internal.inbound.HttpInboundLink.handleDiscrimination(HttpInboundLink.java:444)
    at com.ibm.ws.http.channel.internal.inbound.HttpInboundLink.handleNewRequest(HttpInboundLink.java:378)
    at com.ibm.ws.http.channel.internal.inbound.HttpInboundLink.processRequest(HttpInboundLink.java:278)
    at com.ibm.ws.http.channel.internal.inbound.HttpInboundLink.ready(HttpInboundLink.java:249)
    at com.ibm.ws.tcpchannel.internal.NewConnectionInitialReadCallback.sendToDiscriminators(NewConnectionInitialReadCallback.java:174)
    at com.ibm.ws.tcpchannel.internal.NewConnectionInitialReadCallback.complete(NewConnectionInitialReadCallback.java:83)
    at com.ibm.ws.tcpchannel.internal.WorkQueueManager.requestComplete(WorkQueueManager.java:502)
    at com.ibm.ws.tcpchannel.internal.WorkQueueManager.attemptIO(WorkQueueManager.java:550)
    at com.ibm.ws.tcpchannel.internal.WorkQueueManager.workerRun(WorkQueueManager.java:899)
    at …

我在WebSphere Application Server 8上使用JSF 2.0(Apache myFaces).

我有一个bean,其中包含一个图表列表(jquery HighCharts的数据).对于每个图表,我需要一些JSF组件+一个写为CompositeCompoent的Highchart Wrapper(在这里查看)

所以我使用jsf 2的ui:repeat函数,如下所示:

<?xml version="1.0" encoding="UTF-8" ?>
<ui:composition xmlns="http://www.w3.org/1999/xhtml"
    xmlns:ui="http://java.sun.com/jsf/facelets"
    xmlns:f="http://java.sun.com/jsf/core"
    xmlns:h="http://java.sun.com/jsf/html"
    xmlns:p="http://primefaces.org/ui"
    xmlns:c="http://java.sun.com/jsp/jstl/core"
    xmlns:hc="http://java.sun.com/jsf/composite/chartComponents"
    template="/template/mytemplate.xhtml">

    <ui:define name="content">


        <ui:repeat value="#{chartCtrl.charts }" var="chart" id="chartrepeat" varStatus="chartStatus">
                #{chartStatus.index }
                <h:form id="chartform_#{chartStatus.index }">

                    <!-- some jsf select stuff-->               
                </h:form>

                    #{chartStatus.index }
                    <hc:Chart title="Statistics" id="hcchart_#{chartStatus.index }"
                    <!-- here's the problem-->

                        <ui:repeat value="#{chart.series }" var="serie">
                            <hc:ChartSeries series="#{serie.data }" />
                        </ui:repeat>
                    </hc:Chart>
                    #{chartStatus.index }
            </p:panel>
        </ui:repeat>


        <h:outputScript library="js" name="highcharts.js" />
        <h:outputScript library="js/modules" name="exporting.js" />
        <h:outputScript library="js" name="jquery-1.9.1.min.js" …

我有一个HashSet,它在Graph中存储了一些边.每个Edge都有两个节点.

在图表未定向的情况下,添加副本应该失败:

Edge a = new Edge(new Node("aa"), new Node("bb"));
Edge duplicate = new Edge(new Node("aa"), new Node("bb"));

但是在下面的例子中它起作用:

System.out.println(a.equals(duplicate));

Set<Edge> sete = new HashSet<Edge>();
System.out.println(sete.contains(a));
System.out.println(sete.add(a));
System.out.println(sete.contains(duplicate));
System.out.println(sete.add(duplicate));

Output:
true

false
true
false
true

编辑:好的,现在我添加了一个hashCode方法,适用于定向边.有人可以帮我计算无向边的哈希吗？

public class Edge {
    private Node first, second;

    @Override
    public /boolean equals(Object ob) {
        if (ob instanceof Edge) {
            Edge edge = (Edge) ob;
            if (first.equals(edge.first)
                    && second.equals(edge.second)
                    || first.equals(edge.second)
                    && second.equals(edge.first))
                return true;
        }
        return false;
   }


    @Override
    public int hashCode() {
        int …