小编Cod*_*aru的帖子

我已将WebView放在Scrollview中,而Scrollview又放在viewcontroller的视图中.点击webview时,"tapRecognized"方法不会被调用.

这是我的代码:

    UITapGestureRecognizer *oneFingerTwoTaps = 
      [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapRecognized)] autorelease];

    [oneFingerTwoTaps setNumberOfTapsRequired:1];


// Add the gesture to the view

[[self view] addGestureRecognizer:oneFingerTwoTaps];

我也尝试过使用foll:

[scrollview addGestureRecognizer:oneFingerTwoTaps];

[webview addGestureRecognizer:oneFingerTwoTaps];

请帮忙

MongoDB Stitch:iOS SDK - 注册问题:

我试过这个:

let stitchClient = StitchClient(appId: "<my-app-id>")
stitchClient.register(email: email, password: password).then({ () in

    print("Signed up here")
})
.catch({ (err) in

    print("Sign up fu**ed up: \(err)")
})

总是得到这个:

responseParsingFailed("没有收到服务器的有效数据").

当我点击注册网址时(https://stitch.mongodb.com/api/client/v2.0/app/my-app-name/auth/providers/local-userpass/register/)

使用这些参数({"email":"what@mailinator.com","password":"password"})作为正文的一部分,

服务器返回:

404页面不存在

我做了一些不期望的事情吗？

这是我的任务描述:

给出了由N个整数组成的零索引数组A.

该数组的平衡指数是任何整数P,使得0≤P<N且较低指数的元素之和等于较高指数的元素之和,即A [0] + A 1 + ... + A [P-1] = A [P + 1] + ... + A [N-2] + A [N-1].

假设零元素的总和等于0.如果P = 0或P = N-1,则可能发生这种情况.例如,考虑以下由N = 8个元素组成的数组A:

A[0] = -1
A[1] =  3
A[2] = -4
A[3] =  5
A[4] =  1
A[5] = -6
A[6] =  2
A[7] =  1

P = 1 is an equilibrium index of this array, because:
•   A[0] = ?1 = A[2] + A[3] + A[4] + A[5] + …

当我运行这段代码时:

float angle = startAngle;
int i = 0;

for (float f = self.minNumber; f <= self.maxNumber; f += minorTickIncrement) {
    points[i++] = CGPointMake(centerX + cos(angle) * (radius - tickInset), centerY + sin(angle) * (radius - tickInset));

    CGFloat myTickLength;

    NSLog(@"f : %f",f);
    NSLog(@"tickIncrement : %f",tickIncrement);
    NSLog(@"f / tickIncrement : %f",f / tickIncrement);
    NSLog(@"(int)(f / tickIncrement) : %d",(int)(f / tickIncrement));
    NSLog(@"(f / tickIncrement - (int)(f / tickIncrement)) : %f",(f / tickIncrement - (int)(f / tickIncrement)));
    NSLog(@"fabs((f / tickIncrement - (int)(f / …