小编Jor*_*ark的帖子

我正在制作的是天气预报网站,我需要的是一周的日子(即"星期天","星期一"等).为了得到明天的日期,我只是把"+ 1"放在另一个问题的建议中,但是当它到达星期六时,它会说"未定义".如何在星期六到达时,我将如何实现,+ 1将循环到星期日？提前致谢!

var day=new Date();
var weekday=new Array(7);
weekday[0]="Sunday";
weekday[1]="Monday";
weekday[2]="Tuesday";
weekday[3]="Wednesday";
weekday[4]="Thursday";
weekday[5]="Friday";
weekday[6]="Saturday";

document.getElementById('tomorrow').innerHTML = weekday[day.getDay() + 1];
document.getElementById('twodays').innerHTML = weekday[day.getDay() + 2];
document.getElementById('threedays').innerHTML = weekday[day.getDay() + 3];

我收到此错误:

"无法调用非函数类型的值'HTTPURLResponse？'"

在该部分:

.response { (request, response, data, error)

我想知道是否有人可以帮助我.

Alamofire.download(urlToCall, method: .get) { temporaryURL, response in
    if FileManager.default.fileExists(atPath: finalPath!.path!) {
        do {
            try FileManager.default.removeItem(atPath: finalPath!.path!)
        } catch {
            // Error - handle if required
        }
    }
    return finalPath!

    }
    .response { (request, response, data, error) in

        if error != nil {

        }
        var myDict: NSDictionary?
        let path = finalPath!
        myDict = NSDictionary(contentsOf: path)

        if let dict = myDict {
            success(dict)
        }

        if finalPath != nil {
            //doSomethingWithTheFile(finalPath!, fileName: fileName!) …