小编aku*_*bas的帖子

让应用程序在后台运行

我想保持我的应用程序在后台运行
我有一个应用程序将用户的位置发送到我们的服务器
我有以下代码:

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    LocationManager locationManager;
    String context = Context.LOCATION_SERVICE;
    locationManager = (LocationManager)getSystemService(context);

    Criteria criteria = new Criteria();
    criteria.setAccuracy(Criteria.ACCURACY_FINE);
    criteria.setAltitudeRequired(false);
    criteria.setBearingRequired(false);
    criteria.setCostAllowed(true);
    criteria.setPowerRequirement(Criteria.POWER_LOW);
    String provider = locationManager.getBestProvider(criteria, true);

    updateWithNewLocation(null);

    locationManager.requestLocationUpdates(provider, (10*60*1000), 10,
                                           locationListener);
}
private final LocationListener locationListener = new LocationListener() {
    public void onLocationChanged(Location location) {
      updateWithNewLocation(location);
    }

    public void onProviderDisabled(String provider){
      updateWithNewLocation(null);
    }

    public void onProviderEnabled(String provider){ }
    public void onStatusChanged(String provider, int status, 
                                Bundle extras){ }
  };
  public void updateWithNewLocation(Location location) …
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android background

9
推荐指数
1
解决办法
4万
查看次数

java.lang.RuntimeException:无法在未调用Looper.prepare()的线程内创建处理程序

嗨,我的代码有问题.我的代码是

progressD = ProgressDialog.show(MenuUtama.this, "", "Uploading files to server.....", false);
Thread thread = new Thread(new Runnable(){
       public void run(){
           //doFileUpload();
           try {
            // setiap parameter yang akan dikirim melalui http
            // harus encode agar
            // dapat terbaca dengan baik oleh server
            Cursor c = helper.getAll1(almagId);
            Cursor cr = helper.getUpImage(almagId);
                if(c.moveToFirst()){
                    //progressD = ProgressDialog.show(context, title, message)
                        do{
                            String kdstore = URLEncoder.encode(helper.getKdStore(c).toString(), "utf-8");
                            String nama = URLEncoder.encode(helper.getNama(c).toString(), "utf-8");
                            String alamat = URLEncoder.encode(helper.getAlamat(c).toString(), "utf-8");
                            String kdpos = URLEncoder.encode(helper.getKdPos(c).toString(), "utf-8");
                            String notelp = URLEncoder.encode(helper.getNotel(c).toString(), …
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error-handling android

7
推荐指数
2
解决办法
4万
查看次数

java.lang.illegalargumentexception url中的非法字符

我想要
像这样请求web服务我的参数

urlString = http://ip/autodownload/andro.php?key=apps.apk|2|bla.bla.bla

public void getRequest(String Url) {
    Toast.makeText(this, "Tambah Data " + Url + " ", Toast.LENGTH_SHORT).show();
    HttpClient client = new DefaultHttpClient();
    HttpGet request = new HttpGet(urlString);
    try {
        System.out.println("tes");
        HttpResponse response = client.execute(request);
        Toast.makeText(this,request(response),Toast.LENGTH_SHORT).show();
        String res = EntityUtils.toString(response.getEntity());
        System.out.println(res);
        Update(res);
    } catch (Exception ex) {
        Toast.makeText(this, "Gagal Konek Server !", Toast.LENGTH_SHORT).show();
    }       
}
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如果我在浏览器中运行它没关系,但是当我在android中运行它是这样的错误

10-25 10:24:49.862: ERROR/AndroidRuntime(14602): FATAL EXCEPTION: main
10-25 10:24:49.862: ERROR/AndroidRuntime(14602): java.lang.IllegalArgumentException: Illegal character in query at index 67: http://10.234.152.120/autodownload/andro.php?key=DeliverReceipt.apk|2|com.sat.deliver
10-25 10:24:49.862: ERROR/AndroidRuntime(14602):     at …
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android

4
推荐指数
1
解决办法
1万
查看次数

设置默认值复选框android

我有数据库中的数据与复选框中的值
我尝试设置复选框与数据库中的值,如果数据库非空复选框复选框但如果没有选中空复选框..
我的代码如下:

public void load(){
   final Cursor c = helper.getSat(almagId);
       c.moveToFirst();
   if(c.getString(3) != null){
           ch1.isChecked();
   }
   isi2.setText(c.getString(4));
   if(c.getString(4) != null){
       ch2.isChecked();
   }
   isi3.setText(c.getString(5));
   if(c.getString(5) != null){
       ch3.isChecked();
   }
}
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但它不起作用..我可以解决这个问题吗?谢谢你的反馈:)

checkbox android

3
推荐指数
1
解决办法
2万
查看次数

标签 统计

android ×4

background ×1

checkbox ×1

error-handling ×1