小编Tes*_*ent的帖子

我有这个表:

A:
id
1
2

B:
id a_id
1  1
2  1
3  1

C:
id a_id
1  1
2  1
3  2

我需要这个结果:

A, CountB, CountC
1,      3,      2
2,      0,      1

这个尝试不起作用:

SELECT 
    A.id, COUNT(B.id), COUNT(C.id)
FROM
    A
        LEFT JOIN
    B ON A.id = B.a_id
        LEFT JOIN
    C ON A.id = C.a_id
GROUP BY A.id

如果不使用相关查询,sql句子必须如何？

我如何为表单身份验证提供程序设置success_handler(和failure_handler)？

Silex用这个配置忽略了我:

<?php

use WebFactory\Security\UserProvider;

$app->register(new Silex\Provider\SecurityServiceProvider(), array(
    'security.firewalls' => array(
        'dev' => array(
            'pattern' => '^/(_(profiler|wdt)|css|images|js)/',
            'security' => false
        ),
        'default' => array(
            'pattern' => '^/.*$',
            'anonymous' => true,
            'form' => array(
                'login_path' => '/login',
                'check_path' => '/login_check',
                'success_handler' => 'authentication_handler', //<-- here
                'failure_handler' => 'authentication_handler', //<-- here
            ),
            'logout' => array('logout_path' => '/logout'),
            'users' => $app->share(function () use ($app) {
                        return new UserProvider($app['db']);
                    }),
        ),
    ),
    'security.access_rules' => array(
        array('^/login', 'IS_AUTHENTICATED_ANONYMOUSLY'),
        array('^/private$', 'ROLE_ADMIN'),
    ),
    'security.role_hierarchy' => array(
        'ROLE_SIMPLE_USER' …

我如何使用Doctrine queryBuilder为countDistinct expr设置别名？

$qb->addSelect($qb->expr()->countDistinct('_charges.id'));