我想将查询结果从 BigQuery 导出到本地文件/Google 存储。
我试过 'bq extract' 命令,但它不允许查询作为输入。
Usage: bq extract <source_table> <destination_uris>
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我不想提取整个表,因为该表包含许多不需要的列,我需要聚合数据。
到目前为止,我能找到的唯一解决方法是使用“bq query”命令创建一个表并使用“bq extract”来提取数据。
我正在寻找任何更好的方法来通过执行以下操作来实现这一目标。
bq extract 'select dept_id,sum(sal) from temp.employee
group by dept_id' 'gs://XXXX/employee.csv'
Run Code Online (Sandbox Code Playgroud) 我在一个.ipynb_checkpoints不允许使用文件夹名称写入磁盘空间的环境中工作。
不幸的是,这是 Jupyter Notebook 的默认路径Save and Checkpoint。有没有办法将 Jupyter Notebook 配置为不使用检查点功能或允许不同的文件夹名称?
我必须显示面积大或人口大的国家,但不能同时显示和显示名称、人口和面积。如果我没有错的话,基本上它是一个 XOR 操作。
一个国家的面积超过300万平方公里,或者人口超过2.5亿,就是大国。
我试过这个
SELECT name, population, area
FROM world
WHERE (area > 30000000 | population > 25000000) &
(area < 30000000 & population < 25000000)
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我正在sqlzoo.net上尝试这个- SELECT_from_WORLD_Tutorial: Q.No-8。请选择 SQL 引擎到 SQLSERVER。
latest我Dockerfile在FROM声明中使用了标签:
# Dockerfile
FROM registry.website.com/base-image:latest
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每次我的latest版本更改时,我都需要重新拉出该图像。
不幸的是,docker 只采用缓存版本。
我试过
docker-compose build --no-cache
和
docker-compose up --build --force-recreate project
但它看起来总是这样:
> docker-compose up --build --force-recreate project
Building project
Step 1/12 : FROM registry.website.com/base-image:latest
---> e2a0bcaf3dd7
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任何想法为什么它不起作用?
Run Code Online (Sandbox Code Playgroud)WARNING Application instance <Task pending coro=<__call__() running at /home/developer/projects/tabcon/tabcon_env/lib/python3.5/site-packages/channels/http.py:191> wait_for=<Future pending cb=[_chain_future.<locals>._call_check_cancel() at /usr/lib/python3.5/asyncio/futures.py:431, Task._wakeup()]>> for connection <WebRequest at 0x7ffa40e17b00 method=GET uri=/ clientproto=HTTP/1.1> took too long to shut down and was killed.
出现上述异常,整个服务停止运行。
我在用:
升级我的 Android Studio 后,每当我想生成签名的 Apk 时都会收到此错误(没有任何关于问题所在的详细信息)。我刚构建Apk时没有问题。
The Host name may not be empty
Run Code Online (Sandbox Code Playgroud) Say I have a function:
handleChange = (e) => {
this.setState({ [e.target.id]: e.target.value });
}
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What is the difference between the following:
1.
<FormControl value={this.state.password} onChange={this.handleChange} />
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<FormControl value={this.state.password} onChange={(e) => this.handleChange(e)} />
Run Code Online (Sandbox Code Playgroud) fontScale = 1
fontThickness = 1
# make sure font thickness is an integer, if not, the OpenCV functions that use this may crash
fontThickness = int(fontThickness)
upperLeftTextOriginX = int(imageWidth * 0.05)
upperLeftTextOriginY = int(imageHeight * 0.05)
textSize, baseline = cv2.getTextSize(resultText, fontFace, fontScale, fontThickness)
textSizeWidth, textSizeHeight = textSize
# calculate the lower left origin of the text area based on the text area center, width, and height
lowerLeftTextOriginX = upperLeftTextOriginX
lowerLeftTextOriginY = upperLeftTextOriginY + textSizeHeight
# write the text on …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用 plotly 绘制印度地图,但无法找到一种方法来做到这一点。以下是我为美国尝试的代码。
import pandas as pd
df_sample = pd.read_csv('https://raw.githubusercontent.com/plotly/datasets/master/laucnty16.csv')
df_sample['State FIPS Code'] = df_sample['State FIPS Code'].apply(lambda x: str(x).zfill(2))
df_sample['County FIPS Code'] = df_sample['County FIPS Code'].apply(lambda x: str(x).zfill(3))
df_sample['FIPS'] = df_sample['State FIPS Code'] + df_sample['County FIPS Code']
colorscale = ["#f7fbff","#ebf3fb","#deebf7","#d2e3f3","#c6dbef","#b3d2e9","#9ecae1",
"#85bcdb","#6baed6","#57a0ce","#4292c6","#3082be","#2171b5","#1361a9",
"#08519c","#0b4083","#08306b"]
endpts = list(np.linspace(1, 12, len(colorscale) - 1))
fips = df_sample['FIPS'].tolist()
values = df_sample['Unemployment Rate (%)'].tolist()
fig = ff.create_choropleth(
fips=fips, values=values,
binning_endpoints=endpts,
colorscale=colorscale,
show_state_data=False,
show_hover=True, centroid_marker={'opacity': 0},
asp=2.9, title='USA by Unemployment %',
legend_title='% unemployed'
)
fig.layout.template = None
fig.show() …Run Code Online (Sandbox Code Playgroud) 我正在学习 python 中的多处理。我有以下代码片段:
import time
import concurrent.futures
def wait(seconds):
print(f'Waiting {seconds} seconds...')
time.sleep(seconds)
return f'Done'
if __name__ == "__main__":
with concurrent.futures.ProcessPoolExecutor() as executor:
p = executor.submit(wait,1)
print(p.result())
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运行它给我这个错误:
BrokenProcessPool Traceback (most recent call last)
<ipython-input-19-8eff57e3a077> in <module>
9 with concurrent.futures.ProcessPoolExecutor() as executor:
10 p = executor.submit(do_something,1)
---> 11 print(p.result())
~\.conda\envs\w\lib\concurrent\futures\_base.py in result(self, timeout)
433 raise CancelledError()
434 elif self._state == FINISHED:
--> 435 return self.__get_result()
436 else:
437 raise TimeoutError()
~\.conda\envs\w\lib\concurrent\futures\_base.py in __get_result(self)
382 def __get_result(self):
383 if self._exception:
--> …Run Code Online (Sandbox Code Playgroud) python ×4
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